Statement I: The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association due to dipole-dipole interactions. Statement II: The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding. In the light of the above statements, choose the most appropriate answer:

Solution & Explanation

\textbf{Answer:} (A) Both Statement I and Statement II are correct. \textbf{Solution:} The polar $\mathrm{C}=\mathrm{O}$ group lets aldehydes and ketones associate through dipole-dipole interactions, raising their boiling points above non-polar hydrocarbons of comparable mass (Statement I correct). Lacking an $-\mathrm{OH}$ or $-\mathrm{NH}$, they cannot form intermolecular hydrogen bonds, so their boiling points are lower than alcohols of similar mass (Statement II correct).