Glucose to Glucose-6-Phosphate: The Hexokinase Step

Biology · Respiration in Plants · NEET

The very first step of glycolysis converts glucose into glucose-6-phosphate. The enzyme hexokinase does this by moving one phosphate from ATP onto glucose, so 1 ATP is used (invested) here. Memory hook: "HexoKinase Kicks-in first" — it adds the first phosphate and traps glucose inside the cell.
First Step of Glycolysis: HexokinaseGlucose(6 carbon)Glucose-6-phosphate(activated, trapped)HexokinaseATP → ADP(1 ATP used)First irreversible (committed) step · occurs in cytoplasm
Hexokinase transfers one phosphate from ATP to glucose, forming glucose-6-phosphate. This spends 1 ATP and is the first irreversible (committed) step of glycolysis in the cytoplasm.

Your doubts, answered

Which enzyme catalyses the first step of glycolysis?

Hexokinase. It transfers a phosphate group from ATP onto glucose, making glucose-6-phosphate. NCERT (Ch 12) says both glucose and fructose are phosphorylated to glucose-6-phosphate by the enzyme hexokinase. This is the first reaction of the EMP (glycolysis) pathway and it happens in the cytoplasm.

Does this step use ATP or make ATP?

It USES (spends) 1 ATP. Glycolysis has an early investment phase where energy is put in before energy is later collected. NCERT states ATP is utilised at two steps, and the FIRST is the conversion of glucose into glucose-6-phosphate. So the hexokinase step is an ATP-consuming step, not an ATP-making step.

Why does the cell add a phosphate to glucose right at the start?

Two reasons. First, phosphorylation traps glucose inside the cell because the charged glucose-6-phosphate cannot leak back out through the membrane. Second, adding phosphate makes the molecule more reactive (activated), so the next steps of glycolysis can proceed. This is why the cell spends 1 ATP even though glycolysis is meant to release energy.

Is the hexokinase step reversible or irreversible?

It is irreversible. NEET 2019 directly called it 'the first irreversible reaction of glycolysis.' Because it is committed and one-way, it acts as a control point of the pathway. This is a common NEET fact — remember it as the first committed (irreversible) step.

What is the difference between hexokinase and phosphofructokinase?

Both use ATP, but they act on different molecules. Hexokinase acts FIRST: glucose to glucose-6-phosphate. Phosphofructokinase acts LATER: fructose-6-phosphate to fructose-1,6-bisphosphate. NEET often mixes these two up, so link 'hexo = glucose (first)' and 'phospho-fructo = fructose (second).'

What happens to glucose-6-phosphate after this step?

It isomerises (rearranges) into fructose-6-phosphate. NCERT says the phosphorylated form of glucose then isomerises to produce fructose-6-phosphate, and from there glucose and fructose follow the same steps. So glucose-6-phosphate is a short-lived link between glucose entry and the main glycolytic chain.

⚠️ The NEET trap
The first step of glycolysis produces ATP because glycolysis makes energy.
The first step USES 1 ATP. Glucose-to-glucose-6-phosphate by hexokinase is an ATP-investing (spending) step; ATP is only made later at PGA and PEP steps.
🧠 Early glycolysis = you PAY (invest ATP); late glycolysis = you EARN (make ATP).

Real NEET questions

NEET 2019

Conversion of glucose to glucose-6-phosphate, the first irreversible reaction of glycolysis, is catalyzed by

A · Aldolase
B · Hexokinase
C · Enolase
D · Phosphofructokinase
Solution: In glycolysis, glucose is phosphorylated to glucose-6-phosphate by hexokinase using one ATP; this is the first committed (irreversible) step. Phosphofructokinase acts later (fructose-6-phosphate to fructose-1,6-bisphosphate), aldolase splits fructose-1,6-bisphosphate, and enolase acts near the end. NCERT Ch 12: glucose is phosphorylated to glucose-6-phosphate by the enzyme hexokinase.
NEET 2023

Assertion A: ATP is used at two steps in glycolysis. Reason R: First ATP is used in converting glucose into glucose-6-phosphate and second ATP is used in conversion of fructose-6-phosphate into fructose-1,6-diphosphate. In the light of the above statements, choose the correct answer.

A · Both A and R are true and R is the correct explanation of A
B · Both A and R are true but R is NOT the correct explanation of A
C · A is true but R is false
D · A is false but R is true
Solution: Assertion is true: ATP is utilised at two steps of glycolysis. The Reason names those exact steps correctly — first the glucose-to-glucose-6-phosphate step (hexokinase) and second the fructose-6-phosphate-to-fructose-1,6-bisphosphate step (phosphofructokinase). Since R states precisely the two ATP-investment steps, it correctly explains A.

Solved Respiration in Plants NEET PYQs

Try the real previous-year questions from this chapter — each with the answer and a full solution.

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Frequently asked

Where in the cell does the hexokinase step occur?

In the cytoplasm. All ten reactions of glycolysis, including this first step, happen in the cytoplasm of the cell and are present in all living organisms.

How many ATP are used in the whole glycolysis before any ATP is made?

Two ATP are invested — one at the hexokinase step (glucose to glucose-6-phosphate) and one at the phosphofructokinase step (fructose-6-phosphate to fructose-1,6-bisphosphate).

Can fructose also form glucose-6-phosphate here?

Yes. NCERT says glucose and fructose are both phosphorylated to give glucose-6-phosphate by hexokinase, after sucrose is split into glucose and fructose by invertase.

Why is this step called a committed step?

Because it is irreversible and once glucose is phosphorylated it is locked into the glycolytic pathway. This makes it an important control point of glycolysis for NEET.