Chalcogens (Group 16): The Oxygen Family Explained for NEET

Chemistry · Periodic Classification Of Properties · NEET

Chalcogens are the Group 16 elements: Oxygen (O), Sulphur (S), Selenium (Se), Tellurium (Te), and Polonium (Po). They all have the outer configuration ns2np4, so they need 2 more electrons to fill their shell. This gives them a common valence of 2 and a common -2 oxidation state. Memory hook: "Chalcogens = Ore-formers" (O, S, Se, Te, Po). The word means "ore-forming", because many metal ores are oxides and sulphides.
Chalcogens (Group 16) - Oxygen FamilyValence config ns2np4 | Valence = 8 - 6 = 2 | common state -2O (2s2 2p4) non-metalS (3s2 3p4) non-metalSe (4s2 4p4) metalloidTe (5s2 5p4) metalloidPo (6s2 6p4) metal (no -2)metalliccharacterincreases-2 statemorestable up
Group 16 chalcogens all share ns2np4. Down the group metallic character rises (O, S non-metals to Po metal), so the -2 oxidation state is stable at the top but lost by Polonium at the bottom.

Your doubts, answered

What exactly is a chalcogen and which elements are in the family?

A chalcogen is any element in Group 16 of the periodic table. The family has five main members: Oxygen (O), Sulphur (S), Selenium (Se), Tellurium (Te), and Polonium (Po). A newer radioactive member, Livermorium (Lv), also sits here. For NEET you mainly need the first five. The name 'chalcogen' means 'ore-forming', because many important ores are oxides and sulphides.

What is the electronic configuration of Group 16 elements?

Every chalcogen has the same valence shell pattern: ns2 np4. That means 6 electrons in the outermost shell. For example, Oxygen is 1s2 2s2 2p4, and Sulphur is [Ne] 3s2 3p4. Because the valence configuration is the same, all chalcogens show similar chemical behaviour. This is why they are placed in one vertical column (group).

Why is the valence of chalcogens equal to 2?

Valence is found using the rule 'eight minus outer electrons' for non-metals. Chalcogens have 6 outer electrons, so valence = 8 - 6 = 2. This means they gain or share 2 electrons to complete their octet. That is why oxygen forms H2O and sulphur forms H2S, both using 2 bonds.

Why do chalcogens show a -2 oxidation state?

With 6 outer electrons, a chalcogen needs just 2 more electrons to reach the stable noble gas configuration ns2 np6. When it gains 2 electrons, it reaches the -2 oxidation state, like O(2-) in Na2O or S(2-) in Na2S. This is the most common oxidation state for the lighter members. NEET loves testing that this -2 state gets less common down the group.

Which chalcogen does NOT show the -2 oxidation state, and why?

Polonium (Po) does not show the -2 state. Going down the group, metallic (electropositive) character increases. Po is the heaviest and most metallic chalcogen, so it prefers to lose electrons rather than gain them. The lighter, more electronegative members (O, S, Se, Te) can still form the -2 state. This is a direct NEET 2024 answer.

Is oxygen a chalcogen? It behaves so differently from sulphur.

Yes, oxygen is a chalcogen and is the first member of Group 16. It behaves a bit differently because it is very small, highly electronegative, and has no d-orbitals in its valence shell. This 'anomalous first member' behaviour is normal in the p-block. Oxygen usually shows only -2 (and -1 in peroxides), while sulphur can show +2, +4, and +6 as well.

How do metallic character and oxidation states change down Group 16?

As you go down (O to S to Se to Te to Po), atomic size increases and metallic character increases. Oxygen and sulphur are non-metals, selenium and tellurium are metalloids, and polonium is a metal (and radioactive). Because metallic nature grows downward, the -2 state becomes less stable and higher positive states (+4, +6) become more common in the heavier members.

⚠️ The NEET trap
Students pick Oxygen (O) as the Group 16 element that does not show the -2 oxidation state, thinking oxygen is 'special'.
Polonium (Po) is the correct answer. Po is the most metallic and electropositive chalcogen, so it does not readily gain 2 electrons to form -2. Oxygen actually shows -2 very easily (it is highly electronegative).
🧠 Metallic character increases DOWN the group -> the BOTTOM element (Po) loses the -2 state, not the top one.

Real NEET questions

NEET 2024

Among Group 16 elements, which one does NOT show the -2 oxidation state?

A · Se
B · Te
C · Po
D · O
Solution: Electropositive (metallic) character increases down a group. Polonium (Po) is the heaviest and most metallic Group-16 element, so it prefers to lose electrons rather than gain 2 electrons; hence it does not show the -2 oxidation state. The lighter, more electronegative members (O, Se, Te) readily form the -2 state. Correct answer: (C) Po.

Solved Periodic Classification Of Properties NEET PYQs

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Frequently asked

Why are Group 16 elements called chalcogens?

The name 'chalcogen' comes from Greek and means 'ore-forming'. Many common metal ores exist as oxides and sulphides (for example iron oxide and zinc sulphide), and oxygen and sulphur are Group 16 elements, so the whole family is named after this ore-forming role.

What is the general valence shell configuration of chalcogens?

It is ns2 np4, meaning 6 electrons in the outermost shell. Because all members share this configuration, they show similar chemical properties and the same valence of 2.

What is the difference between chalcogens and halogens?

Chalcogens are Group 16 with configuration ns2 np4, valence 2, and common oxidation state -2. Halogens are Group 17 with configuration ns2 np5, valence 1, and common oxidation state -1. Halogens are more reactive non-metals because they need only 1 electron to complete their octet.

Are all chalcogens non-metals?

No. Oxygen and sulphur are non-metals, selenium and tellurium are metalloids, and polonium is a radioactive metal. Metallic character increases as you move down the group.

Which oxidation states does sulphur commonly show?

Sulphur commonly shows -2 (as in H2S), +4 (as in SO2), and +6 (as in SO3 and H2SO4). Unlike oxygen, sulphur has vacant d-orbitals, so it can expand its octet and reach higher positive states.