Chemistry · Periodic Classification Of Properties · NEET
Break the number into single digits: 1, 1, 9. Now replace each digit with its root: 1 = un, 1 = un, 9 = enn. Join them in order: un + un + enn = ununenn. Add '-ium' at the end (but drop the double 'i' or double 'n' if it looks odd) to get ununennium. So Z = 119 is ununennium, symbol Uue. Do not try to guess a real name like the way older elements got named; for NEET you only spell out the digits.
There are only ten roots, one for each digit 0 to 9: 0 = nil, 1 = un, 2 = bi, 3 = tri, 4 = quad, 5 = pent, 6 = hex, 7 = sept, 8 = oct, 9 = enn. This is straight from NCERT Table 3.4. If you know these ten, you can name any element above 100. A common exam trick is to give you the name and ask for the atomic number, so learn the roots both ways (name to number and number to name).
Take the first letter of each root you used, in the same order, and capitalise only the first letter. For Z = 114 the roots are un (1), un (1), quad (4), so the symbol is Uuq. For Z = 119 the roots are un, un, enn, so the symbol is Uue. The symbol always has three letters because the atomic number always has three digits in this range.
NCERT explains that naming a new element used to be the right of the discoverer, and this caused fights (for example one element was called both Kurchatovium and Rutherfordium by different countries). Also these very heavy atoms are so unstable that only a few atoms are ever made, so the discovery takes long to confirm. So IUPAC gives a temporary systematic name from the atomic number until the real name is voted on and approved.
Yes. Unnilunium is the systematic name for Z = 101, because un = 1, nil = 0, un = 1 gives 101. The permanent IUPAC name for element 101 is Mendelevium (Md). NEET 2020 asked exactly this match. Once an element gets its official permanent name, the systematic name is only used in old questions, but NEET still tests it, so remember both the systematic name and the real name for elements like Md (101), Lr (103), Sg (106).
Split the name into its roots (they always come before '-ium'), then convert each root back to a digit. Example: Unnilseptium = un (1) + nil (0) + sept (7) = 107. Example: Ununoctium = un (1) + un (1) + oct (8) = 118. Reading the roots in order gives you the digits of the atomic number directly.
The IUPAC name of an element with atomic number 119 is:
Match the IUPAC provisional (systematic) names with their official names. (a) Unnilunium (b) Unniltrium (c) Unnilhexium (d) Unununnium with (i) Mendelevium (ii) Lawrencium (iii) Seaborgium (iv) Darmstadtium. Which one is correct?
Identify the incorrect statement. (Option B stated: The IUPAC name of the element with atomic number 107 is Unnilseptium.)
Try the real previous-year questions from this chapter — each with the answer and a full solution.
You must know the systematic method (the digit roots) for sure, because that is directly asked. Also learn a few common matches that NEET has asked: 101 = Mendelevium (Md), 103 = Lawrencium (Lr), 106 = Seaborgium (Sg), 110 = Darmstadtium (Ds), 111 = Roentgenium (Rg). Memorising all of them is not needed, but these appear in match questions.
Because every atomic number above 100 has exactly three digits (100 to 999 range in practice), and you take one letter for each digit's root. So the symbol is always three letters, like Uuq for 114 or Uue for 119.
The suffix is always '-ium'. You spell out all the digit roots first and then add -ium. This is why every systematic name of a heavy element ends in -ium.
It is a temporary systematic name for Z = 107. The permanent IUPAC name for 107 is Bohrium (Bh). NEET still uses the systematic name in questions, so you should be able to convert Unnilseptium back to 107 quickly.
Both are IUPAC systems but they are unrelated. Organic IUPAC naming builds a name from the carbon chain and functional groups. Here, for heavy elements, the name is built only from the digits of the atomic number plus -ium. Do not mix the two rule sets.
