Periodicity of Valence and Oxidation States in the Periodic Table

Chemistry · Periodic Classification Of Properties · NEET

For main-group (representative) elements, valence usually equals the number of electrons in the outermost shell, OR equals 8 minus that number. Across a period valence first rises (1 to 4) then falls back to 0 for the noble gas; down a group it stays the same because the outer electron count stays the same. Memory hook: "Outer electrons OR eight-minus" — pick whichever is smaller and easier for that element.
Valence across Period 3 (Na to Ar)NaMgAlSiPSClAr1e2e3e4e5e6e7e8e12343210valence = outer electronsvalence = 8 - outer electronsnoble gas = 0
Valence across Period 3 rises 1 to 4 (using "number of outer electrons") then falls 3 to 1 (using "8 minus outer electrons"), reaching 0 at argon. This is the periodic pattern NEET expects you to reproduce.

Your doubts, answered

How do I find the valence of an element just from its outer electrons?

Take the number of electrons in the outermost shell (valence electrons). For Group 1 (ns1) valence is 1, Group 2 (ns2) valence is 2, Group 13 valence is 3, Group 14 valence is 4. After Group 14 it is easier to use the second rule: valence = 8 minus outer electrons. So Group 15 (5 outer) has valence 3, Group 16 (6 outer) has valence 2, Group 17 (7 outer) has valence 1, and Group 18 (8 outer) has valence 0. NCERT states this exactly: valence is 'equal to the number of electrons in the outermost orbitals and/or equal to eight minus the number of outermost electrons.'

Why does valence rise from 1 to 4 and then fall back to 0 across a period?

Early in a period an atom has few outer electrons, so it loses or shares them — valence equals that small count (1, 2, 3, 4). After the middle, the atom is closer to a full octet, so it gains or shares only the electrons it still needs — valence becomes 8 minus the outer count (3, 2, 1). The noble gas already has a full shell (ns2 np6), so it needs nothing and its valence is 0. This is why valence goes 1, 2, 3, 4, 3, 2, 1, 0 across Period 3 (Na to Ar).

What is the difference between valence and oxidation state?

Valence is just a whole number that tells how many bonds an atom forms — it has no plus or minus sign. Oxidation state is valence WITH a sign, decided by comparing electronegativity. NCERT gives the classic example: in OF2 oxygen is +2 (F is more electronegative), but in Na2O oxygen is -2 (Na is less electronegative). So the same element (oxygen) can have different oxidation states, but the term oxidation state is now often used in place of valence.

How do I calculate the oxidation state of nitrogen in HNO3, NO and NH4Cl?

Use fixed values: H = +1, O = -2, and make the whole formula add to its charge (0 for a neutral molecule). In HNO3: (+1) + N + 3(-2) = 0, so N = +5. In NO: N + (-2) = 0, so N = +2. In N2 the element is alone, so N = 0. In NH4Cl the NH4+ ion has N + 4(+1) = +1, so N = -3. Decreasing order: HNO3 (+5) > NO (+2) > N2 (0) > NH4Cl (-3). This is exactly NEET 2018.

Why do transition (d-block) elements show many oxidation states but main-group elements do not?

In transition elements the (n-1)d and ns electrons are close in energy, so a variable number of them can take part in bonding. That is why Mn shows +2 all the way to +7, and its states differ by one unit (V is +2, +3, +4, +5). Main-group elements mostly use only their outer s and p electrons, so their common oxidation states differ by two (like +2 and +4 in tin and lead) because a lone pair either bonds or stays out.

Why is valence the same for all elements down a single group?

Elements in the same group have the same number of electrons in their outermost shell (the same valence-shell configuration, like ns1 for all alkali metals). Valence depends on this outer electron count, not on how many inner shells there are. So Li, Na, K all have valence 1, and O, S, Se all have valence 2. This is why groups are also called 'families' with similar chemistry.

⚠️ The NEET trap
Ordering nitrogen oxidation states by how 'strong' or 'common' the compound looks, e.g. putting NH4Cl high because it is a familiar salt.
Always compute the oxidation state number using H=+1, O=-2 and charge balance. HNO3 (+5) > NO (+2) > N2 (0) > NH4Cl (-3). The correct decreasing order is C.
🧠 Oxidation state is a MATH answer, not a 'which looks important' guess — set the equation to the charge and solve.

Real NEET questions

NEET 2018

The correct order of N-compounds in its decreasing order of oxidation states is

A · HNO3, NH4Cl, NO, N2
B · HNO3, NO, NH4Cl, N2
C · HNO3, NO, N2, NH4Cl
D · NH4Cl, N2, NO, HNO3
Solution: Find the oxidation state of nitrogen in each, using H = +1 and O = -2. HNO3: +1 + N + 3(-2) = 0, so N = +5. NO: N + (-2) = 0, so N = +2. N2: free element, N = 0. NH4Cl: in NH4+, N + 4(+1) = +1, so N = -3. Decreasing order = +5 > +2 > 0 > -3, i.e. HNO3 > NO > N2 > NH4Cl. Answer C.
NEET 2024

Among Group 16 elements, which one does NOT show the -2 oxidation state?

A · Se
B · Te
C · Po
D · O
Solution: Metallic (electropositive) character increases down a group. Po is the heaviest, most metallic Group-16 element, so it prefers to lose electrons rather than gain them and does not show the -2 state. The lighter, more electronegative members O, Se and Te readily form the -2 oxidation state. Answer C.
NEET 2017

It is because of inability of ns2 electrons of the valence shell to participate in bonding that

A · Sn2+ is reducing while Pb4+ is oxidising
B · Sn2+ is oxidising while Pb4+ is reducing
C · Sn2+ and Pb2+ are both oxidising and reducing
D · Sn4+ is reducing while Pb4+ is oxidising
Solution: The reluctance of the ns2 (lone) pair to bond, growing down a p-block group, is the inert pair effect. In lead the +2 state is more stable than +4, so Pb4+ is easily reduced to Pb2+ and acts as an oxidising agent. In tin the +4 state is more stable, so Sn2+ is easily oxidised to Sn4+ and acts as a reducing agent. Answer A. (This links valence/oxidation-state stability to the next concept, the inert pair effect.)

Solved Periodic Classification Of Properties NEET PYQs

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Frequently asked

Is valence always equal to the group number?

For s-block and Groups 13-14 of the p-block, valence equals the number of outer electrons (1, 2, 3, 4). But for Groups 15-18 it is easier and correct to use valence = 8 minus outer electrons (3, 2, 1, 0). So it is not always the plain group number, especially on the right side of the table.

Can one element have more than one valence or oxidation state?

Yes. Many elements show more than one, especially transition metals (Mn shows +2 to +7) and heavy p-block elements (Pb shows +2 and +4). NCERT calls these 'variable oxidation states'. Main-group states usually differ by 2, transition-metal states usually differ by 1.

Why is oxygen +2 in OF2 but -2 in Na2O?

Oxidation state depends on which atom is more electronegative. Fluorine is more electronegative than oxygen, so in OF2 oxygen is assigned +2. Sodium is far less electronegative than oxygen, so in Na2O oxygen is -2. Same element, different partner, different sign.

Do noble gases have a valence?

Their normal (common) valence is 0 because their outer shell ns2 np6 is already complete, so they do not usually gain, lose or share electrons. Heavier noble gases like Xe can be forced to form compounds (XeF2, XeF6), but the standard periodic-trend valence taught for NEET is 0.