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NEET 2016 Phase 1 · PhysicsPrevious Year Question

Match the corresponding entries of Column 1 with Column 2 (where m is the magnification produced by the mirror). Column 1: (A) m = −2 (B) m = −1/2 (C) m = +2 (D) m = +1/2 Column 2: (a) Convex mirror (b) Concave mirror (c) Real image (d) Virtual image

Answer: (A) A → b and c; B → b and c; C → b and d; D → a and d. Answer: (A) A → b and c; B → b and c; C → b and d; D → a and d Solution: Magnification m = −v/u.

  1. A.A → b and c; B → b and c; C → b and d; D → a and d✓
  2. B.A → a and c; B → a and d; C → a and b; D → c and d
  3. C.A → a and d; B → b and c; C → b and d; D → b and c
  4. D.A → c and d; B → b and d; C → b and c; D → a and d

Correct Answer

(A) A → b and c; B → b and c; C → b and d; D → a and d

Solution & Explanation

Answer: (A) A → b and c; B → b and c; C → b and d; D → a and d Solution: Magnification m = −v/u. A negative m means an inverted, real image; a positive m means an erect, virtual image. A magnified image (|m| > 1 or here treated by the standard NEET key) and the sign decide the mirror type. (A) m = −2: real (m negative), magnified inverted image → only a concave mirror gives a real image, so concave (b) and real image (c). (B) m = −1/2: real (m negative), diminished inverted image → again a concave mirror, so concave (b) and real image (c). (C) m = +2: virtual (m positive), magnified erect image → concave mirror with object inside focus, so concave (b) and virtual image (d). (D) m = +1/2: virtual (m positive), diminished erect image → characteristic of a convex mirror, so convex (a) and virtual image (d). Hence A → b,c; B → b,c; C → b,d; D → a,d.

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