NEET 2016 Phase 1 · PhysicsJoule heatingPrevious Year Question
The charge through a resistance R varies with time as Q = at - bt (a, b positive constants). The total heat produced in R is:
Answer: (A) aR/(6b). \textbf{Answer:} (1) aR/(6b) \textbf{Solution:} i = dQ/dt = a - 2bt; i = 0 at t = a/(2b).
- A.aR/(6b)✓
- B.aR/(3b)
- C.aR/(2b)
- D.aR/b
Correct Answer
(A) aR/(6b)
Solution & Explanation
\textbf{Answer:} (1) aR/(6b) \textbf{Solution:} i = dQ/dt = a - 2bt; i = 0 at t = a/(2b). H = ^{a/2b} iR dt = R(a-2bt)dt = aR/(6b).
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