NEET 2016 Phase 2 · PhysicsCircular radiusPrevious Year Question

An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57 × 10⁻² T. If the value of e/m is 1.76 × 10¹¹ C/kg, the frequency of revolution of the electron is:

Answer: (A) 1 GHz. Answer: (A) Solution: Cyclotron frequency f = qB/(2πm) = (e/m)·B/(2π).

  1. A.1 GHz
  2. B.100 MHz
  3. C.62.8 MHz
  4. D.6.28 MHz

Correct Answer

(A) 1 GHz

Solution & Explanation

Answer: (A) Solution: Cyclotron frequency f = qB/(2πm) = (e/m)·B/(2π). f = (1.76 × 10¹¹ × 3.57 × 10⁻²)/(2 × 3.14) f ≈ (6.28 × 10⁹)/6.28 ≈ 1 × 10⁹ Hz = 1 GHz. → option A.

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