NEET 2016 Phase 2 · PhysicsPrevious Year Question

Two identical glass (µ_g = 3/2) equiconvex lenses of focal length f each are kept in contact. The space between the two lenses is filled with water (µ_w = 4/3). The focal length of the combination is

Answer: (D) 3f/4. Answer: (D) 3f/4 Solution: For one equiconvex glass lens, both radii are equal in magnitude R, so 1/f = (µ_g − 1)(2/R) = (3/2 − 1)(2/R) = 1/R Hence 1/R = 1/f.

  1. A.f/3
  2. B.f
  3. C.4f/3
  4. D.3f/4

Correct Answer

(D) 3f/4

Solution & Explanation

Answer: (D) 3f/4 Solution: For one equiconvex glass lens, both radii are equal in magnitude R, so 1/f = (µ_g − 1)(2/R) = (3/2 − 1)(2/R) = 1/R Hence 1/R = 1/f. The water between the two lenses acts as an equiconcave lens (radii −R and +R as seen by water): 1/f_w = (µ_w − 1)(−2/R) = (4/3 − 1)(−2/R) = −(1/3)(2/R) = −2/(3R) = −2/(3f) The combination is three thin lenses in contact: 1/F = 1/f + 1/f_w + 1/f = 1/R + 1/R − 2/(3R) 1/F = 2/f − 2/(3f) = (6 − 2)/(3f) = 4/(3f) Therefore F = 3f/4.

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