The figure shows a - diagram with three isotherms at K, K and K. Four processes I, II, III and IV start from a common initial state. Match each process with its type:\\ List-I (Process): I, II, III, IV\\ List-II (Type): (a) Adiabatic, (b) Isobaric, (c) Isochoric, (d) Isothermal.\\ Which of the following is the correct matching?
Answer: (B) Ic, IIa, IIId, IVb. \textbf{Answer:} (b) Ic, IIa, IIId, IVb \textbf{Solution:} Starting from the common state, identify each process by its geometry on the - diagram: Process I is a vertical line (constant volume) \textbf{isochoric} (c).

- A.Ia, IIc, IIId, IVb
- B.Ic, IIa, IIId, IVb✓
- C.Id, IIa, IIIc, IVb
- D.Ib, IIc, IIIa, IVd
Correct Answer
(B) Ic, IIa, IIId, IVb
Solution & Explanation
\textbf{Answer:} (b) Ic, IIa, IIId, IVb \textbf{Solution:} Starting from the common state, identify each process by its geometry on the - diagram: Process I is a vertical line (constant volume) \textbf{isochoric} (c). Process II is a steep falling curve, steeper than the isotherm, crossing to a lower-temperature isotherm \textbf{adiabatic} (a), since an adiabat is steeper than an isotherm and lowers the temperature on expansion. Process III follows along an isotherm (same temperature curve) \textbf{isothermal} (d). Process IV is a horizontal line (constant pressure) \textbf{isobaric} (b). Hence Ic, IIa, IIId, IVb, which is option (b).
