Consider the following species: CN^+, CN^-, NO and CN. Which of these will have the highest bond order?

Correct answer: (B) CN^-. Answer: (B) CN^- Solution: Using MOT bond order = 1/2(N_b - N_a): CN^- (14 e^-) has bond order 3; CN and NO have bond order 2.5; CN^+ has bond order 2. Hence CN^- has the highest bond order.

NEET 2018 · ChemistryMO theoryPrevious Year Question

Consider the following species: $CN X^{+}$ , $CN X^{-}$ , $NO$ and $CN$ . Which of these will have the highest bond order?

Answer: (B) $CN X^{-}$ . \textbf{Answer:} (B) $CN X^{-}$ \textbf{Solution:} Using MOT bond order $= \frac{1}{2} (N_{b} - N_{a})$ : $CN X^{-}$ ( $14$ e $^{-}$ ) has bond order $3$ ; $CN$ and $NO$ have bond order $2.5$ ; $CN X^{+}$ has bond order $2$ .

A. $CN X^{+}$
B. $CN X^{-}$ ✓
C. $NO$
D. $CN$

Correct Answer

(B) $CN X^{-}$

Solution & Explanation

\textbf{Answer:} (B) $CN X^{-}$ \textbf{Solution:} Using MOT bond order $= \frac{1}{2} (N_{b} - N_{a})$ : $CN X^{-}$ ( $14$ e $^{-}$ ) has bond order $3$ ; $CN$ and $NO$ have bond order $2.5$ ; $CN X^{+}$ has bond order $2$ . Hence $CN X^{-}$ has the highest bond order.

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Consider the following species: CNX+, CNX−, NO and CN. Which of these will have the highest bond order?

Solution & Explanation

More NEET PYQ solutions

Consider the following species: $CN X^{+}$ , $CN X^{-}$ , $NO$ and $CN$ . Which of these will have the highest bond order?