NEET 2018 · PhysicsResistivityPrevious Year Question
A carbon resistor of (47 ± 4.7) k is to be marked with rings of different colours for its identification. The colour code sequence will be:
Answer: (B) Yellow–Violet–Orange–Silver. \textbf{Answer:} (2) Yellow–Violet–Orange–Silver \textbf{Solution:} 47 k = 4710 .
- A.Yellow–Green–Violet–Gold
- B.Yellow–Violet–Orange–Silver✓
- C.Violet–Yellow–Orange–Silver
- D.Green–Orange–Violet–Gold
Correct Answer
(B) Yellow–Violet–Orange–Silver
Solution & Explanation
\textbf{Answer:} (2) Yellow–Violet–Orange–Silver \textbf{Solution:} 47 k = 4710 . First digit 4Yellow, second 7Violet, multiplier 10Orange. Tolerance 4.7/47 = ±10%Silver. Sequence: Yellow–Violet–Orange–Silver.
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