NEET 2018 · PhysicsPrevious Year Question

A pendulum hung from the roof of a tall building moves freely to and fro as a simple harmonic oscillator. The acceleration of the bob is 20 m/s² at a distance of 5 m from the mean position. The time period of oscillation is

Answer: (B) π s. Correct Answer (B): π s Step-by-step solution: 1.

  1. A.2 s
  2. B.π s
  3. C.2π s
  4. D.1 s

Correct Answer

(B) π s

Solution & Explanation

Correct Answer (B): π s Step-by-step solution: 1. In SHM, magnitude of acceleration |a| = ω²x. 2. 20 = ω² × 5 → ω² = 4 → ω = 2 rad/s. 3. T = 2π/ω = 2π/2 = π s.

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