The standard electrode potential (E^°) values of Al^3+/Al, Ag+/Ag, K+/K and Cr^3+/Cr are -1.66 V, 0.80 V, -2.93 V and -0.74 V, respectively. The correct decreasing order of the reducing power of the metals is:

NEET 2019 Odisha · ChemistryGalvanic & EMFPrevious Year Question

The standard electrode potential ( $E^{\circ}$ ) values of $Al X^{3 +} / Al$ , $Ag X^{+} / Ag$ , $K X^{+} / K$ and $Cr X^{3 +} / Cr$ are $- 1.66 V$ , $0.80 V$ , $- 2.93 V$ and $- 0.74 V$ , respectively. The correct decreasing order of the reducing power of the metals is:

Answer: (B) $K$ > $Al$ > $Cr$ > $Ag$ . \textbf{Answer:} (B) $K$ > $Al$ > $Cr$ > $Ag$ \textbf{Solution:} Reducing power is inversely related to the standard reduction potential: the more negative (lower) the $E^{\circ}$ , the stronger the reducing agent.

A. $Ag$ > $Cr$ > $Al$ > $K$
B. $K$ > $Al$ > $Cr$ > $Ag$ ✓
C. $K$ > $Al$ > $Ag$ > $Cr$
D. $Al$ > $K$ > $Ag$ > $Cr$

Correct Answer

(B) $K$ > $Al$ > $Cr$ > $Ag$

Solution & Explanation

\textbf{Answer:} (B) $K$ > $Al$ > $Cr$ > $Ag$ \textbf{Solution:} Reducing power is inversely related to the standard reduction potential: the more negative (lower) the $E^{\circ}$ , the stronger the reducing agent. Arranging $E^{\circ}$ from lowest to highest: $E_{K X^{+} / K}^{\circ} = - 2.93 < E_{Al X^{3 +} / Al}^{\circ} = - 1.66 < E_{Cr X^{3 +} / Cr}^{\circ} = - 0.74 < E_{Ag X^{+} / Ag}^{\circ} = + 0.80 V$ Therefore the decreasing order of reducing power is: $K$ > $Al$ > $Cr$ > $Ag$ .

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The standard electrode potential (E∘) values of AlX3+/Al, AgX+/Ag, KX+/K and CrX3+/Cr are −1.66 V, 0.80 V, −2.93 V and −0.74 V, respectively. The correct decreasing order of the reducing power of the metals is:

Solution & Explanation

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The standard electrode potential ( $E^{\circ}$ ) values of $Al X^{3 +} / Al$ , $Ag X^{+} / Ag$ , $K X^{+} / K$ and $Cr X^{3 +} / Cr$ are $- 1.66 V$ , $0.80 V$ , $- 2.93 V$ and $- 0.74 V$ , respectively. The correct decreasing order of the reducing power of the metals is: