NEET 2020 · PhysicsDielectricsPrevious Year Question
The capacitance of a parallel plate capacitor with air as medium is 6 microF. With the introduction of a dielectric medium, the capacitance becomes 30 microF. The permittivity of the medium is: (eps0 = 8.85 × 10⁻¹² C² N⁻¹ m⁻²)
Answer: (A) 0.44 × 10⁻¹⁰ C² N⁻¹ m⁻². Answer: (a) Solution: K = C/C₀ = 30/6 = 5.
- A.0.44 × 10⁻¹⁰ C² N⁻¹ m⁻²✓
- B.5.00 C² N⁻¹ m⁻²
- C.0.44 × 10⁻¹³ C² N⁻¹ m⁻²
- D.1.77 × 10⁻¹² C² N⁻¹ m⁻²
Correct Answer
(A) 0.44 × 10⁻¹⁰ C² N⁻¹ m⁻²
Solution & Explanation
Answer: (a) Solution: K = C/C₀ = 30/6 = 5. Permittivity ε = Kε₀ = 5 × 8.85 × 10⁻¹² = 44.25 × 10⁻¹² ≈ 0.44 × 10⁻¹⁰ C²N⁻¹m⁻². → option (a).
🎯
43,000+ questions in हिंदी & English · one-tap toggle
Open →📚Practice all NEET Physics PYQs chapter-wise →💡Don't get it? Learn the Electrostatic Potential And Capacitance concepts →Practice NEET 2020 Physics — free, with instant solutions
43,000+ NEET questions solved step-by-step, chapter-wise, in the MedicNEET app.
More NEET PYQ solutions
PhysThe plates of a parallel plate capacitor are separated by d. Two slabs of different dielectric constant K1 and K2 with thickness 3d/8 and d/2 respectively are inserted in the capacitor. Due to this, the capacitance becomes two times larger than when there is nothing between the plates. If K1/K2 = 1.25, the value of K1 is:PhysPolar molecules are the molecules:PhysA parallel-plate capacitor of area A, plate separation d and capacitance C is filled with four dielectric materials having dielectric constants k1, k2, k3 and k4 as shown in the figure below. If a single dielectric material is to be used to have the same capacitance C in this capacitor, then its dielectric constant k is given byPhysAn electric dipole with dipole moment 5 × 10⁻⁶ C·m is aligned with the direction of a uniform electric field of magnitude 4 × 10⁵ N/C. The dipole is then rotated through an angle of 60° with respect to the electric field. The change in the potential energy of the dipole is:PhysTwo identical charged conducting spheres A and B have their centres separated by a certain distance. Charge on each sphere is q and the force of repulsion between them is F. A third identical uncharged conducting sphere is brought in contact with sphere A first and then with B and finally removed from both. New force of repulsion between spheres A and B (radii negligible vs separation, treated as point charges) is best given as:PhysA sphere of radius R is carved out of a uniform solid sphere of radius 2R (internally tangent, so its centre is at distance R from the big centre). The ratio of the moment of inertia of the small sphere to that of the remaining part, both about the Y-axis through the big sphere's centre, is:PhysThe Sun rotates once in 27 days. If it expanded to twice its present radius (uniform-density sphere, no external influence), its new period would be about:PhysA uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall, making 60° with the wall; its lower end rests on a rough horizontal floor. The friction force exerted by the floor is: (g = 10 m/s²)