Match the floral formulae in List I with the families in List II. List I (Floral formula) (a) % ⚥ K(5) C1+2+(2) A(9)+1 G1 (b) ⊕ ⚥ K(5) C(5) A5 G(2) (c) ⊕ ⚥ P(3+3) A(3+3) G(3) (d) ⊕ ⚥ K2+2 C4 A2+4 G(2) List II (Family) (i) Brassicaceae (ii) Liliaceae (iii) Fabaceae (iv) Solanaceae Choose the correct answer from the options given below. (NEET 2021)
Answer: (C) (a)-(iii); (b)-(iv); (c)-(ii); (d)-(i). Each floral diagram is identified from diagnostic features: Fabaceae (zygomorphic, vexillary corolla, diadelphous stamens, monocarpellary marginal ovary), Solanaceae (actinomorphic, 5 epipetalous stamens, bicarpellary axile ovary with oblique septum), Liliaceae (trimerous, perianth of 6 tepals, 6 stamens, tricarpellary syncarpous ovary) and Brassicaceae (cruciform corolla, tetradynamous stamens, bicarpellary ovary with false septum).
- A.(a)-(ii); (b)-(iii); (c)-(iv); (d)-(i)
- B.(a)-(iv); (b)-(ii); (c)-(i); (d)-(iii)
- C.(a)-(iii); (b)-(iv); (c)-(ii); (d)-(i)✓
- D.(a)-(i); (b)-(ii); (c)-(iii); (d)-(iv)
Correct Answer
(C) (a)-(iii); (b)-(iv); (c)-(ii); (d)-(i)
Solution & Explanation
Each floral diagram is identified from diagnostic features: Fabaceae (zygomorphic, vexillary corolla, diadelphous stamens, monocarpellary marginal ovary), Solanaceae (actinomorphic, 5 epipetalous stamens, bicarpellary axile ovary with oblique septum), Liliaceae (trimerous, perianth of 6 tepals, 6 stamens, tricarpellary syncarpous ovary) and Brassicaceae (cruciform corolla, tetradynamous stamens, bicarpellary ovary with false septum). Matching gives (a)-Fabaceae(iii), (b)-Solanaceae(iv), (c)-Liliaceae(ii), (d)-Brassicaceae(i), which is option C. NCERT Reference: NCERT (Class XI Morphology — Fabaceae & Liliaceae, pre-2023 rationalisation text) (Note: this specific content was rationalised out of the 2026-27 NCERT reprint; grounded in pre-2023 NCERT text.)