The conductivity of centimolar solution of $\mathrm{KCl}$ at $25{}^{\circ }\text{C}$ is $0.0210{\text{ohm}}^{-1}{\text{cm}}^{-1}$ and the resistance of the cell containing the solution at $25{}^{\circ }\text{C}$ is $60\text{ohm}$. The value of cell constant is

Answer: (C) $1.26{\text{cm}}^{-1}$. \textbf{Answer:} (C) $1.26{\text{cm}}^{-1}$ \textbf{Solution:} The cell constant is defined by $G^{\ast }=\frac{l}{A}=R\kappa$, where $R$ is the measured resistance and $\kappa$ the conductivity: $G^{\ast }=R\times \kappa =60\times 0.0210=1.26{\text{cm}}^{-1}$