NEET 2023 Phase 1 · PhysicsSpectral seriesPrevious Year Question
In hydrogen spectrum, the shortest wavelength in the Balmer series is λ. The shortest wavelength in the Brackett series is:
Answer: (B) 4λ. Answer: (b) 4λ Solution: Shortest wavelength = series limit (n=∞).
- A.2λ
- B.4λ✓
- C.9λ
- D.16λ
Correct Answer
(B) 4λ
Solution & Explanation
Answer: (b) 4λ Solution: Shortest wavelength = series limit (n=∞). Balmer (∞→2): 1/λ = R/4 = R/2². Brackett (∞→4): 1/λ' = R/16 = R/4². Ratio λ'/λ = (1/λ)/(1/λ') = (R/4)/(R/16) = 4 → λ' = 4λ.
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