NEET 2023 Phase 1 · PhysicsLoop centre fieldPrevious Year Question

A very long conducting wire is bent in a semi-circular shape from A to B as shown in figure. The magnetic field at point P for steady current configuration is given by:

Answer: (C) (μ₀i/4R)(1 + 2/π) pointed away from the page. Answer: (C) Solution: The configuration is two collinear straight (semi-infinite) wire segments plus a semicircular arc of radius R, with P at the centre of the arc.

NEET 2023 Phase 1 Physics question — A very long conducting wire is bent in a semi-circular shape from A to B as shown in…

A.μ₀i/4R pointed into the page
B.μ₀i/4R pointed away from the page
C.(μ₀i/4R)(1 + 2/π) pointed away from the page✓
D.(μ₀i/4R)(1 + 2/π) pointed into the page

Correct Answer

Solution & Explanation

Answer: (C) Solution: The configuration is two collinear straight (semi-infinite) wire segments plus a semicircular arc of radius R, with P at the centre of the arc. Semicircular arc at its centre: B_arc = μ₀i/(4R). Each straight segment is a semi-infinite wire with P at perpendicular distance R from its end; each gives B_straight = μ₀i/(4πR). Two such segments: 2 × μ₀i/(4πR) = μ₀i/(2πR) = (μ₀i/4R)(2/π). All three contributions are in the same direction (out of the page) at P. B = (μ₀i/4R) + (μ₀i/4R)(2/π) = (μ₀i/4R)(1 + 2/π), pointed away from the page.

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