NEET 2023 Phase 2 · PhysicsGauss spheresPrevious Year Question
If a conducting sphere of radius R is charged, then the electric field at a distance r (r > R) from the centre of the sphere would be (V = potential on the surface of the sphere):
Answer: (A) RV / r². Answer: (a) Solution: For a charged conducting sphere of radius R carrying charge Q: Surface potential V = kQ/R, so kQ = VR.
- A.RV / r²✓
- B.V / r
- C.rV / R²
- D.R²V / r³
Correct Answer
(A) RV / r²
Solution & Explanation
Answer: (a) Solution: For a charged conducting sphere of radius R carrying charge Q: Surface potential V = kQ/R, so kQ = VR. For r > R, the sphere behaves as a point charge at its centre: E = kQ / r² = (VR) / r² = RV / r². Hence option (a).
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