NEET 2023 Phase 2 · PhysicsEnergy levelsPrevious Year Question
The ground state energy of hydrogen atom is –13.6 eV. The energy needed to ionize hydrogen atom from its second excited state will be:
Answer: (A) 1.51 eV. Answer: (a) 1.51 eV Solution: Second excited state is n=3.
- A.1.51 eV✓
- B.3.4 eV
- C.13.6 eV
- D.6.8 eV
Correct Answer
(A) 1.51 eV
Solution & Explanation
Answer: (a) 1.51 eV Solution: Second excited state is n=3. E₃ = −13.6/3² = −13.6/9 = −1.51 eV. Energy needed to ionize (remove electron to n=∞, E=0) = 0 − (−1.51) = 1.51 eV.
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