NEET 2023 Phase 2 · PhysicsConductor spherePrevious Year Question
If a conducting sphere of radius R is charged. Then the electric field at a distance r (r > R) from the centre of the sphere would be, (V = potential on the surface of the sphere)
Answer: (A) RV/r². Answer: (a) Solution: Surface potential V = kQ/R → kQ = RV.
- A.RV/r²✓
- B.V/r
- C.rV/R²
- D.R² V/r³
Correct Answer
(A) RV/r²
Solution & Explanation
Answer: (a) Solution: Surface potential V = kQ/R → kQ = RV. Field outside: E = kQ/r² = RV/r². → option (a).
🎯
43,000+ questions in हिंदी & English · one-tap toggle
Open →📚Practice all NEET Physics PYQs chapter-wise →💡Don't get it? Learn the Electrostatic Potential And Capacitance concepts →Practice NEET 2023 Phase 2 Physics — free, with instant solutions
43,000+ NEET questions solved step-by-step, chapter-wise, in the MedicNEET app.
More NEET PYQ solutions
PhysA thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is (Take 1/4πε₀ = 9 × 10⁹ SI units).PhysTwo hollow conducting spheres of radii R1 and R2 (R1 >> R2) have equal charges. The potential would be:PhysTwenty seven drops of same size are charged at 220 V each. They combine to form a bigger drop. Calculate the potential of the bigger drop.PhysAn electric dipole with dipole moment 5 × 10⁻⁶ C·m is aligned with the direction of a uniform electric field of magnitude 4 × 10⁵ N/C. The dipole is then rotated through an angle of 60° with respect to the electric field. The change in the potential energy of the dipole is:PhysTwo identical charged conducting spheres A and B have their centres separated by a certain distance. Charge on each sphere is q and the force of repulsion between them is F. A third identical uncharged conducting sphere is brought in contact with sphere A first and then with B and finally removed from both. New force of repulsion between spheres A and B (radii negligible vs separation, treated as point charges) is best given as:PhysThe plates of a parallel plate capacitor are separated by d. Two slabs of different dielectric constant K1 and K2 with thickness 3d/8 and d/2 respectively are inserted in the capacitor. Due to this, the capacitance becomes two times larger than when there is nothing between the plates. If K1/K2 = 1.25, the value of K1 is:PhysA sphere of radius R is carved out of a uniform solid sphere of radius 2R (internally tangent, so its centre is at distance R from the big centre). The ratio of the moment of inertia of the small sphere to that of the remaining part, both about the Y-axis through the big sphere's centre, is:PhysThe Sun rotates once in 27 days. If it expanded to twice its present radius (uniform-density sphere, no external influence), its new period would be about: