NEET 2023 Phase 2 · PhysicsPrevious Year Question
A simple pendulum oscillating in air has a period of √3 s. If it is completely immersed in a non-viscous liquid whose density is one-fourth that of the material of the bob, the new period is
Answer: (A) 2 s. Correct Answer (A): 2 s Step-by-step solution: 1.
- A.2 s✓
- B.√3/2 s
- C.2√3 s
- D.2/√3 s
Correct Answer
(A) 2 s
Solution & Explanation
Correct Answer (A): 2 s Step-by-step solution: 1. Buoyancy reduces the effective gravity: g_eff = g(1 − ρ_liquid/ρ_bob) = g(1 − 1/4) = 3g/4. 2. T = 2π√(L/g), so T′/T = √(g/g_eff) = √(4/3) = 2/√3. 3. T′ = T × 2/√3 = √3 × 2/√3 = 2 s.
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