NEET 2023 Phase 2 · PhysicsPrevious Year Question
A horizontal ray of light is incident on the right-angled prism with prism angle 6°. If the refractive index of the material of the prism is 1.5, then the angle of emergence will be:
Answer: (C) 9°. Answer: (C) 9° Solution: For a thin (small-angle) prism, the deviation δ = (µ − 1)A = (1.5 − 1)(6°) = 0.5 × 6° = 3°.
- A.4°
- B.6°
- C.9°✓
- D.10°
Correct Answer
(C) 9°
Solution & Explanation
Answer: (C) 9° Solution: For a thin (small-angle) prism, the deviation δ = (µ − 1)A = (1.5 − 1)(6°) = 0.5 × 6° = 3°. The incident ray is horizontal and strikes the first face normally (no bending there), so the entire deviation appears at the second face. The emergent ray turns by δ = 3° relative to its incoming direction inside. Measuring the angle of emergence (with respect to the normal of the emergent face), the geometry gives e = 9°. (Using i + e = A + δ with the ray entering along the normal of the first face, the emergence angle works out to 9°.)
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