NEET 2026 (Phase 1) · PhysicsPrevious Year Question
Savitha, a Class XI student, performs an experiment to find the effective length L of a simple pendulum. She records the time for 30 oscillations as 60 s. The length she calculates is (take π² = 9.8 and g = 9.8 m/s²)
- A.0.75 m
- B.1.5 m
- C.2 m
- D.1 m✓
Correct Answer
(D) 1 m
Solution & Explanation
Correct Answer (D): 1 m Step-by-step solution: 1. Time period T = 60 s / 30 = 2 s. 2. T = 2π√(L/g) → L = g(T/2π)² = g·T²/(4π²). 3. L = 9.8 × 4 / (4 × 9.8) = 9.8 × 4 / 39.2 = 1 m.
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