NEET 2026 (Phase 1) · PhysicsPrevious Year Question
The magnitude and direction of the acceleration produced in a body of mass 5 kg when two mutually perpendicular forces 8 N and 6 N act on it are respectively:
- A.$20\ \mathrm{m/s^2};\ \tan^{-1}\!\frac{4}{3}$ with the 8 N force
- B.$2\ \mathrm{m/s^2};\ \tan^{-1}\!\frac{3}{4}$ with the 6 N force
- C.$2\ \mathrm{m/s^2};\ \tan^{-1}\!\frac{4}{3}$ with the 8 N force
- D.$2\ \mathrm{m/s^2};\ \tan^{-1}\!\frac{3}{4}$ with the 8 N force✓
Correct Answer
(D) $2\ \mathrm{m/s^2};\ \tan^{-1}\!\frac{3}{4}$ with the 8 N force
Solution & Explanation
\textbf{Answer:} (d) $2\ \mathrm{m/s^2};\ \tan^{-1}\!\frac{3}{4}$ with the 8 N force \textbf{Solution:} Resultant force $=\sqrt{8^2+6^2}=10$ N, so $a=\dfrac{10}{5}=2\ \mathrm{m/s^2}$. Direction $=\tan^{-1}\!\frac{6}{8}=\tan^{-1}\!\frac{3}{4}$ measured from the 8 N force.
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