LC Oscillations and Energy Exchange

Physics · Alternating Current · NEET

In an LC circuit, a charged capacitor and an inductor keep passing energy back and forth: electric energy in the capacitor turns into magnetic energy in the inductor, then back again. The total energy stays the same (ideal case), and this back-and-forth repeats at frequency f = 1/(2 pi root(LC)). Memory hook: LC = "Electric spring + Magnetic mass" — same as a pendulum swinging between height and speed.
Energy Exchange in an LC CircuitElectric energy in C = q^2/(2C)Magnetic energy in L = (1/2)L i^2q max, i=0all electricq=0, i maxall magneticq max (reversed)energy swings back and forthTotal energy q^2/(2C) + (1/2)L i^2 = constant | f = 1/(2 pi root(LC))
Energy sloshes between the capacitor (electric, red points) and inductor (magnetic, green point) every quarter cycle; the total stays constant in the ideal case, and the swing repeats at f = 1/(2 pi root(LC)).

Your doubts, answered

Is LC oscillation the same as resonance in an LCR circuit?

They use the SAME frequency formula but are different situations. LC oscillation is a FREE oscillation: a charged capacitor and an inductor exchange energy on their own, with no external source. Resonance is a DRIVEN case: an ac source pushes an LCR circuit, and current becomes maximum when the source frequency matches the natural frequency 1/(2 pi root(LC)). So the LC natural frequency f = 1/(2 pi root(LC)) is the bridge between the two topics.

Where exactly is the energy stored at each moment?

Energy sits in two places. In the capacitor as electric energy = q^2 / (2C), and in the inductor as magnetic energy = (1/2) L i^2. When the capacitor is fully charged, all energy is electric and current is zero. A quarter cycle later the capacitor is empty, current is maximum, and all energy is magnetic. The sum q^2/(2C) + (1/2)L i^2 stays constant in the ideal case.

Why does the current keep flowing even after the capacitor fully discharges?

Because of the inductor. An inductor opposes any change in current (its back emf). When the capacitor becomes empty, the current is at maximum, and the inductor keeps that current flowing for a moment. This flowing current then charges the capacitor the OTHER way. That is why the circuit does not stop at zero charge but keeps oscillating, like a pendulum that does not stop at the bottom.

Do I plug frequency f or angular frequency omega into the formula?

Both exist, do not mix them. Angular frequency omega = 1/root(LC) (units rad/s). Ordinary frequency f = omega / (2 pi) = 1/(2 pi root(LC)) (units Hz). NEET options are usually in Hz or kHz, so you almost always need f = 1/(2 pi root(LC)). If the option is in rad/s, use omega = 1/root(LC).

What starts the oscillation if there is no battery?

You first give the capacitor a charge (connect it briefly to a source, then remove the source). That stored electric energy is the starting push. Once the capacitor is charged and the switch connects it to the inductor, the energy exchange begins by itself. No continuous source is needed for an ideal LC circuit to keep oscillating.

⚠️ The NEET trap
Using omega = 1/root(LC) directly as the answer when the options are in Hz (kHz).
Convert: f = omega/(2 pi) = 1/(2 pi root(LC)). For L = 10 mH, C = 1 uF, f = 1/(2 pi x 10^-4) = 1.59 kHz, NOT 10^4 rad/s.
🧠 Options in Hz or kHz -> divide by 2 pi. Options in rad/s -> keep omega. Check the unit before you tick.

Real NEET questions

NEET 2023 Phase 1

In a series LCR circuit, the inductance L is 10 mH, capacitance C is 1 uF and resistance R is 100 ohm. The frequency at which resonance occurs is:

A · 15.9 rad/s
B · 15.9 kHz
C · 1.59 rad/s
D · 1.59 kHz
Solution: Resonance in an LCR circuit occurs at the natural LC frequency (the same frequency at which an LC circuit oscillates freely). Use f = 1/(2 pi root(LC)). Step 1: LC = (10 x 10^-3) x (1 x 10^-6) = 10^-8. Step 2: root(LC) = root(10^-8) = 10^-4. Step 3: f = 1/(2 pi x 10^-4) = 10^4/(2 pi) = 10^4/6.28. Step 4: f = 1592 Hz = 1.59 kHz. Note: R plays no role in the resonant/LC frequency. Answer: D.

Solved Alternating Current NEET PYQs

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Frequently asked

What is the natural frequency of an LC circuit?

The angular natural frequency is omega = 1/root(LC) rad/s, and the ordinary frequency is f = 1/(2 pi root(LC)) Hz. This is the rate at which energy swings between the capacitor and the inductor.

Is total energy really conserved in LC oscillations?

In an ideal LC circuit (no resistance) yes, total energy q^2/(2C) + (1/2)L i^2 is constant. In a real circuit some resistance is always present, so energy slowly leaks as heat and the oscillations die down (damped). NEET usually assumes the ideal case.

What is the analogy for LC oscillations?

A mass on a spring, or a pendulum. The capacitor is like the spring (stores potential/electric energy), the inductor is like the mass (stores kinetic/magnetic energy). Charge q is like position, and current i is like velocity.

At what instant is the current maximum in an LC circuit?

When the capacitor is fully discharged (q = 0). At that moment all the energy is magnetic, stored in the inductor, so (1/2)L i^2 is maximum and i is at its peak value.

Does the LC frequency depend on the initial charge given to the capacitor?

No. The frequency f = 1/(2 pi root(LC)) depends only on L and C, not on how much charge you start with. More starting charge only makes the swings bigger (larger amplitude), not faster.