Solving v x B Cross Product Component Problems

Physics · Moving Charges And Magnetism · NEET

To find the magnetic force F = q(v x B) when v and B are given in i, j, k form, write a 3x3 determinant with i, j, k in the top row, the v components in the second row, and the B components in the third row. Expand it to get the three force components. Memory hook: "top row unit vectors, then v, then B" - the vector that pushes (v) always sits above the field (B).
F = q (v x B): Determinant Method|ijk||vxvyvz| <- velocity (top)|BxByBz| <- field (below)i-part = vy·Bz - vz·Byj-part = -(vx·Bz - vz·Bx)k-part = vx·By - vy·BxMiddle term carries the MINUS sign
The i, j, k determinant for F = q(v x B): velocity components go in the second row, field in the third, and the middle j-term always carries a minus sign.

Your doubts, answered

How do I actually expand v x B when both are in i, j, k form?

Set up a 3x3 determinant. Row 1 = i, j, k. Row 2 = velocity components (vx, vy, vz). Row 3 = field components (Bx, By, Bz). Then: i-part = (vy·Bz - vz·By), j-part = -(vx·Bz - vz·Bx), k-part = (vx·By - vy·Bx). Multiply the whole thing by q. Example: v = 2i + 4j + 6k, B = -6i - 6j - 8k gives i-part = (4)(-8) - (6)(-6) = 4. Always cross-multiply diagonally and subtract.

Which row comes first, v or B?

For F = q(v x B), the velocity v goes in the SECOND row (just below i, j, k) and B goes in the THIRD row. Order matters because cross product is not commutative: v x B = -(B x v). If you swap the rows, every sign flips and your force points the wrong way. Rule: the thing being multiplied first (v) sits on top.

Why does the middle (j) term have a minus sign?

When you expand a determinant, the cofactor signs alternate + - +. So the i-term is positive, the j-term carries a minus, and the k-term is positive again. Students who forget this minus get the j-component with the wrong sign and pick the wrong option. Always write it as j-part = -(vx·Bz - vz·Bx).

How do I work backwards to find B when F and v are given?

In NEET you usually do NOT solve the messy equations. Instead, take q = 1 so F = v x B, then test each option. Plug the given B option into the determinant, expand, and see which one reproduces the given F exactly. This 'plug and check' is faster and safer than algebra under exam pressure.

Is v x B the same as B x v?

No. They are equal in magnitude but opposite in direction: v x B = -(B x v). This is the number-one silent mistake. If a question writes F = qv x B, keep v on top. Never reorder to make the arithmetic 'nicer' - you will flip the sign of the force.

⚠️ The NEET trap
Placing B above v in the determinant, or forgetting the minus sign on the j-component, so the answer comes out with reversed signs (a distractor option is always waiting for this).
Keep v in the second row and B in the third row for F = q(v x B), and write the j-term as -(vx·Bz - vz·Bx). Then plug-and-check the options for a fast, sign-safe answer.
🧠 The determinant row order and the middle minus sign are where NTA sets the trap.

Real NEET questions

2021

In the product F = q(v x B) = q(vx i + vy j + vz k) x (Bx i + By j + Bz k), for q = 1 and v = 2i + 4j + 6k and F = 4i - 20j + 12k, what is the complete expression for B?

A · 8i + 8j - 6k
B · 6i + 6j - 8k
C · -8i - 8j - 6k
D · -6i - 6j - 8k
Solution: With q = 1, F = v x B. Rather than solving equations, test the options. Try B = -6i - 6j - 8k. Set up the determinant: row1 = i, j, k; row2 = 2, 4, 6; row3 = -6, -6, -8. i-part = (4)(-8) - (6)(-6) = -32 + 36 = 4. j-part = -[(2)(-8) - (6)(-6)] = -[-16 + 36] = -20. k-part = (2)(-6) - (4)(-6) = -12 + 24 = 12. This gives F = 4i - 20j + 12k, exactly the given force. So B = -6i - 6j - 8k, option D.

Solved Moving Charges And Magnetism NEET PYQs

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Frequently asked

What is the fastest way to solve these in NEET?

Set q = 1 (or pull q out), then plug each option's B into the i, j, k determinant and check which reproduces the given force. Plug-and-check beats algebra.

Do I need to normalise or find magnitude?

Not for component problems. You just match the three components (i, j, k) with the given force vector. Magnitude questions are a different type.

What if the force has a zero component?

That is a clue: it means v and B are arranged so that one determinant term cancels. Use it to eliminate options quickly instead of expanding fully.

Does the charge sign matter?

Yes. A negative q (like an electron) flips the direction of F. Keep q with its sign when you multiply the determinant result.

How is this different from the velocity selector topic?

Here you only handle the magnetic term q(v x B). In a velocity selector you balance the electric force qE against qvB so net force is zero - that is the next concept to study.