Magnetic Moment of Coils Bent into Different Shapes

Physics · Moving Charges And Magnetism · NEET

When one fixed-length wire is bent into different shapes (circle, square, triangle), the magnetic moment is always m = NIA, but N (number of turns) and A (area enclosed by one turn) both change. The rule: fewer sides means a bigger single loop, so a circle gives the largest moment and a triangle the smallest for the same wire and current. Memory hook: "Same wire, more turns means smaller area — the shape that hugs the most space wins the moment."
Same wire length L, same current I — different shapesN=1Circlelargest area → largest mN=3Squaremedium areaN=4Trianglesmallest area → smallest mm = N I A (turns N = L ÷ perimeter of one loop)
One fixed-length wire wound into a circle (1 turn), square (3 turns) and triangle (4 turns). More sides enclose more area per turn, so for the same wire and current the circle gives the biggest magnetic moment m = NIA and the triangle the smallest.

Your doubts, answered

I bent the same wire into 2 turns instead of 1. Did the magnetic moment go up because N doubled?

No, it goes down. When you make more turns from a fixed wire, each turn becomes smaller. If total length is L, one turn has radius r and area proportional to r squared. With N turns, each turn uses length L/N, so its radius is r/N and its area is (r/N) squared, which is A/N squared. Then m = N times I times A/N squared = IA/N. So m falls as 1/N. More turns from the same wire always means a smaller moment.

How do I find N when a wire of length 12a is bent into a square of side a?

N is total wire length divided by one loop's perimeter. A square of side a has perimeter 4a. So N = 12a / 4a = 3 turns. For a triangle of side a, perimeter is 3a, so N = 12a / 3a = 4 turns. Always divide total length by the shape's perimeter to get how many complete loops you can wind.

For the same wire and current, which shape gives the biggest magnetic moment?

The circle. For a fixed length of wire (fixed perimeter), a circle encloses the most area, then a square, then an equilateral triangle. Since m = NIA and the circle packs the largest area into one turn, it gives the largest moment. This is the isoperimetric idea: more sides (up to a circle) enclose more area for the same perimeter.

Do I use the shape's perimeter or its area in the formula?

Both, but for different jobs. Use the perimeter to find N (turns = total length / perimeter). Use the area of one single turn in m = NIA. Students often mix these up. The perimeter never enters the moment directly; it only tells you how many turns you can make.

⚠️ The NEET trap
Bending the wire into more turns must raise the magnetic moment because N is bigger in m = NIA.
With a fixed-length wire, more turns make each turn smaller, so area drops as 1/N squared. Net result m = IA/N, which decreases. The moment goes DOWN, not up.
🧠 NTA loves giving a fixed wire length. Never treat N as free — every extra turn steals area from the loop.

Real NEET questions

2021

A uniform conducting wire of length 12a and resistance R is wound up as a current carrying coil in the shape of (i) an equilateral triangle of side a, (ii) a square of side a. The magnetic dipole moments of the coil in each case respectively are:

A · 3 Ia² and 4 Ia²
B · 4 Ia² and 3 Ia²
C · √3 Ia² and 3 Ia²
D · √3 Ia² and Ia²
Solution: Use m = NIA. Triangle: perimeter of one turn = 3a, so N = 12a / 3a = 4 turns. Area of one equilateral triangle = (√3/4)a². m₁ = N I A = 4 × I × (√3/4)a² = √3 I a². Square: perimeter of one turn = 4a, so N = 12a / 4a = 3 turns. Area of one square = a². m₂ = N I A = 3 × I × a² = 3 I a². So the moments are √3 Ia² and 3 Ia², option C.
2025

A 2 A current is flowing through two different small circular copper coils having radii ratio 1 : 2. The ratio of their respective magnetic moments will be:

A · 2 : 1
B · 4 : 1
C · 1 : 4
D · 1 : 2
Solution: Magnetic moment of a single-turn coil: m = I A = I (π r²). The current is the same (2 A) for both coils, so m is proportional to r². Ratio = r₁² : r₂² = 1² : 2² = 1 : 4, option C.

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Frequently asked

What is the formula for the magnetic moment of a coil?

m = NIA, where N is the number of turns, I is the current in amperes, and A is the area of one turn in square metres. The unit of m is ampere metre squared (A m²) and its direction is given by the right-hand rule, along the axis of the coil.

Why does the magnetic moment change when the shape changes but the wire is the same?

Because both N and A change. A fixed wire length can be wound into more turns of a smaller shape (raising N but cutting A), or fewer turns of a larger shape. Since m = NIA depends on the actual area enclosed, the shape that encloses the most area per unit perimeter (the circle) gives the highest moment.

Does resistance of the wire affect the magnetic moment?

No, resistance is not in the formula m = NIA. Resistance only matters if the question asks for the current through a given voltage. Once the current I is fixed, the moment depends only on N and A.

How is the direction of the magnetic moment found?

Curl the fingers of your right hand along the direction of current flow in the loop; your thumb points along the magnetic moment vector, perpendicular to the plane of the loop. This is the same as the direction of the magnetic field on the loop's axis.