Resolving Power of a Microscope: Formula and Meaning

Physics · Wave Optics · NEET

Resolving power of a microscope is how well it separates two very close points as two, not one blur. Its formula is RP = 2 n sinB / (1.22 lambda), and the smallest gap it can resolve (limit of resolution) is d = 1.22 lambda / (2 n sinB). Memory hook: "Small wavelength, big cone = you see the detail." A smaller lambda (blue or UV light) and a larger n sinB (numerical aperture) both make the microscope sharper.
Resolving Power of a Microscopetwo points, gap dobjective (n sinB)BRP = 2 n sinB / (1.22 lambda)d = 1.22 lambda / (2 n sinB)smaller lambda -> higher RPbigger n sinB -> higher RPn sinB = numerical aperture
A microscope resolves two points separated by distance d when their diffraction discs stay apart. Resolving power rises with a smaller wavelength lambda and a larger numerical aperture n sinB (wide cone B and high-index medium n, as with oil immersion).

Your doubts, answered

Is resolving power the same as magnification?

No. Magnification only makes the image bigger. Resolving power is about detail: can you see two close points as two separate points? A microscope can magnify a blur into a bigger blur with no new detail. Beyond the resolving limit, extra magnification is called empty magnification. So high magnification without high resolving power is useless.

What is the exact formula for resolving power of a microscope?

Resolving power RP = 2 n sinB / (1.22 lambda). Here lambda is the wavelength of light used, n is the refractive index of the medium between the object and the objective lens, and B is the half-angle of the light cone entering the objective. The quantity n sinB is called the numerical aperture (NA). The smallest distance it can resolve is d = 1.22 lambda / (2 n sinB).

Why does a smaller wavelength give higher resolving power?

Resolving power is proportional to 1/lambda. Diffraction spreads light less when the wavelength is smaller, so the diffraction discs of two nearby points stay separate. That is why we use blue light or UV and electron microscopes for fine detail: a smaller lambda means a smaller limit of resolution d, so finer objects can be seen distinctly.

What is the limit of resolution of a microscope?

The limit of resolution is the smallest distance d between two points that can still be seen as two. It is the reciprocal of resolving power: d = 1.22 lambda / (2 n sinB). A smaller d means a better microscope. Note the microscope limit depends on the distance d, while the telescope limit is an angle 1.22 lambda / D. Do not mix them up.

How can I increase the resolving power of a microscope?

Two ways: use light of smaller wavelength (blue instead of red, or UV), and increase the numerical aperture n sinB. NA is raised by using a wide-cone objective (large B) and by placing an oil of high refractive index n between the object and the lens. This is why oil-immersion objectives are used in biology labs.

Does resolving power of a microscope depend on the diameter of the lens?

For a microscope, we write it using numerical aperture (n sinB), not the plain diameter D. The diameter form 1.22 lambda / D is used for a telescope, where the object is far away. Confusing the two is a common exam mistake. For a microscope think numerical aperture; for a telescope think objective diameter.

⚠️ The NEET trap
Resolving power is proportional to wavelength, so longer wavelength light gives a sharper microscope.
Resolving power is proportional to 1/lambda. Longer wavelength means MORE diffraction spread and LOWER resolving power. Smaller lambda (blue or UV) gives higher resolving power.
🧠 RP goes UP when lambda goes DOWN. Small light waves squeeze into small gaps.

Real NEET questions

NEET 2017

The ratio of resolving powers of an optical microscope for two wavelengths lambda1 = 4000 A and lambda2 = 6000 A is

A · 8 : 27
B · 9 : 4
C · 3 : 2
D · 16 : 81
Solution: Step 1: Resolving power RP = 2 n sinB / (1.22 lambda), so for the same microscope RP is proportional to 1/lambda. Step 2: Therefore RP1 : RP2 = (1/lambda1) : (1/lambda2) = lambda2 : lambda1. Step 3: Put values: lambda2 : lambda1 = 6000 : 4000 = 3 : 2. Answer: (C) 3 : 2. Trap: do not cube or square the ratio; RP varies as the first power of 1/lambda.

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Frequently asked

What does n sinB mean in the microscope formula?

n sinB is the numerical aperture (NA). n is the refractive index of the medium between object and objective; B is the half-angle of the cone of light collected by the objective. A larger NA collects more diffracted light and gives higher resolving power.

Why is oil used in a microscope objective?

Oil has a high refractive index n (about 1.5) compared to air (1.0). Placing oil between the sample and the objective raises the numerical aperture n sinB, which increases resolving power and lets you see finer detail.

Is the microscope resolving power an angle or a distance?

It is set by a distance. The limit of resolution is the smallest separation d = 1.22 lambda / (2 n sinB) between two points. The telescope limit, by contrast, is the smallest angle 1.22 lambda / D.

Why do electron microscopes see more than light microscopes?

Electrons have a very small de Broglie wavelength, far smaller than visible light. Since resolving power is proportional to 1/lambda, a tiny lambda gives an extremely high resolving power, so electron microscopes reveal atomic-scale detail.

Does resolving power depend on the intensity or brightness of light?

No. Resolving power depends only on the wavelength lambda and the numerical aperture n sinB. Making the light brighter does not help separate two close points; only a smaller lambda or larger NA does.