Open Organ Pipe: Fundamental Frequency and Harmonics

Physics · Waves · NEET

An open organ pipe is open at BOTH ends, so it has an antinode at each end. Its fundamental frequency is f = v/2L, and it produces ALL harmonics: f, 2f, 3f, 4f... (both odd and even). Memory hook: "Open = All" — an open pipe is open to every harmonic, just like a string fixed at both ends.
Open Organ Pipe — Modes (antinode at both ends)1st harmonicf = v/2L1 node2nd harmonic2f = v/L2 nodes3rd harmonic3f = 3v/2L3 nodes● = nodeboth ends= antinodesHarmonics present: f, 2f, 3f, 4f... (ALL) → f_n = n(v/2L)
First three modes of an open organ pipe. Both ends are displacement antinodes, so all harmonics f, 2f, 3f... are allowed. The nth harmonic has n nodes and frequency f_n = n(v/2L).

Your doubts, answered

Why is there an antinode at BOTH ends of an open organ pipe?

An open end connects to the free outside air, so the air molecules there are free to vibrate with maximum displacement. Maximum displacement means a displacement antinode. Since both ends are open, both ends must be antinodes. The lowest mode that fits an antinode at each end has exactly one node in the middle, giving length L = lambda/2, so lambda = 2L and f = v/2L.

Does an open organ pipe produce even harmonics too?

Yes. An open pipe produces ALL harmonics: f, 2f, 3f, 4f, 5f... Both odd and even harmonics are present. The nth harmonic is f_n = n(v/2L) for n = 1, 2, 3, 4... This is the key difference from a closed pipe, which gives only odd harmonics.

What is the difference between harmonic and overtone in an open pipe?

Harmonic counts from the fundamental: 1st harmonic = f, 2nd harmonic = 2f, 3rd = 3f. Overtone counts the tones ABOVE the fundamental: 1st overtone = 2nd harmonic = 2f, 2nd overtone = 3rd harmonic = 3f. So for an open pipe: nth overtone = (n+1)th harmonic. Mixing these up is the most common exam mistake.

Why is the fundamental of an open pipe v/2L and not v/4L?

v/4L is the closed-pipe fundamental (node at closed end, antinode at open end, length = lambda/4). An open pipe has antinodes at both ends, so the shortest fitting wave is length = lambda/2, giving f = v/2L. That is why an open pipe of the same length sounds an octave higher (twice the frequency) than a closed pipe.

How many nodes does the nth harmonic of an open pipe have?

For the nth harmonic of an open pipe, the number of nodes equals n. Fundamental (1st harmonic) has 1 node, 2nd harmonic has 2 nodes, 5th harmonic has 5 nodes. The number of antinodes is n+1 (because both ends are antinodes).

⚠️ The NEET trap
Treating an open pipe like a closed pipe and using f = v/4L, or saying an open pipe gives only odd harmonics.
Open pipe: fundamental f = v/2L and it gives ALL harmonics (f, 2f, 3f, 4f...). Only the CLOSED pipe uses v/4L and odd harmonics.
🧠 Two open ends = two antinodes = ALL harmonics with f = v/2L. Do not borrow the closed-pipe formula.

Real NEET questions

2023

The ratio of the fundamental frequency of an open pipe to that of a closed pipe of the same length is:

A · 1 : 2
B · 2 : 1
C · 1 : 3
D · 3 : 1
Solution: Open pipe fundamental = v/(2L). Closed pipe fundamental = v/(4L). Ratio = [v/(2L)] / [v/(4L)] = (4L)/(2L) = 2. So the ratio is 2 : 1. The open pipe sounds an octave higher for the same length.
2016

The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe of length L. The length of the open pipe is:

A · L
B · 2L
C · L/2
D · 4L
Solution: Open pipe 2nd overtone = 3rd harmonic = 3v/(2L_open). Closed pipe 1st overtone = 3rd harmonic = 3v/(4L). Equate: 3v/(2L_open) = 3v/(4L). Cancel 3v: 1/(2L_open) = 1/(4L), so 2L_open = 4L, giving L_open = 2L.
2023

The 4th overtone of a closed organ pipe has the same frequency as the 3rd overtone of an open pipe. The ratio of the length of the closed pipe to the length of the open pipe is:

A · 9 : 8
B · 7 : 9
C · 8 : 9
D · 9 : 7
Solution: Closed pipe (odd harmonics only): 4th overtone = 9th harmonic, so f_c = 9v/(4L_c). Open pipe (all harmonics): 3rd overtone = 4th harmonic, so f_o = 4v/(2L_o) = 2v/L_o. Equate f_c = f_o: 9v/(4L_c) = 2v/L_o. Cross-multiply: 9L_o = 8L_c, so L_c/L_o = 9/8 = 9 : 8.

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Frequently asked

What is the fundamental frequency of an open organ pipe?

f = v/2L, where v is the speed of sound in the air column and L is the length of the pipe. This is the lowest note the pipe can produce.

Which harmonics are present in an open organ pipe?

All harmonics are present: f, 2f, 3f, 4f, 5f... The general formula is f_n = n(v/2L) for n = 1, 2, 3, 4...

Is an open pipe louder or higher-pitched than a closed pipe?

For the same length, an open pipe has double the fundamental frequency of a closed pipe (v/2L vs v/4L), so it sounds one octave higher in pitch.

How does temperature affect the pipe's frequency?

The speed of sound v increases with temperature (v is proportional to the square root of absolute temperature). Since f = v/2L, higher temperature raises every harmonic frequency of the pipe.

Why do open pipes sound richer than closed pipes?

An open pipe contains both even and odd harmonics, while a closed pipe has only odd harmonics. More harmonics give a fuller, richer tone, which is why open pipes are common in musical instruments like the flute.