Meselson and Stahl Experiment: Proof of Semiconservative DNA Replication

Biology · Molecular Basis of Inheritance · NEET

Meselson and Stahl (1958) grew E. coli in heavy 15N medium so its DNA became heavy, then shifted the cells to light 14N medium. After one round of replication all DNA was of intermediate (hybrid) density, and after two rounds there was a mix of light and hybrid DNA. This result proved DNA replication is semiconservative. Memory hook: "Heavy parents give half-heavy children" (one old strand + one new strand in every daughter DNA).
Meselson-Stahl: DNA density after replication in 14NParent (15N)1st generation2nd generationheavyhybridlighthybridAll hybrid after 1 gen; light + hybrid after 2 gen = semiconservative
CsCl density banding of E. coli DNA: heavy 15N parent DNA becomes fully hybrid after one replication in 14N, then splits into light and hybrid bands after two replications. This banding pattern is the proof of semiconservative replication.

Your doubts, answered

What exactly did the Meselson and Stahl experiment prove?

It proved that DNA replication is semiconservative. This means each new DNA molecule keeps one old (parental) strand and makes one new strand. It does not prove conservative or dispersive replication. For NEET, remember: first experimental proof of semiconservative replication, shown in E. coli.

Why did they use 15N and 14N nitrogen?

Nitrogen is present in the nitrogen bases of DNA. 15N is a heavy isotope and 14N is the normal light isotope. Growing E. coli in 15N makes the DNA heavy; shifting to 14N makes new strands light. This weight difference lets them tell old DNA from new DNA. Note: 15N is not radioactive, it is just heavier.

What is hybrid or intermediate DNA?

After one round of replication in 14N medium, every DNA molecule has one heavy 15N old strand and one light 14N new strand. Its density is exactly between heavy and light, so it is called hybrid or intermediate DNA. Seeing a single hybrid band after one generation is the key proof of semiconservative replication.

How did they separate DNA by weight?

They used density gradient centrifugation in a cesium chloride (CsCl) solution. Heavier DNA settles lower and lighter DNA stays higher, forming bands at different positions. The position of the band tells you whether the DNA is heavy, light, or hybrid.

Was the experiment done on a plant or a bacterium?

It was first done in a bacterium, Escherichia coli (E. coli). Only later was semiconservative replication shown in higher organisms such as plants (Taylor's work on Vicia faba). NEET has directly asked this: the answer is Bacterium, not Plant.

What results appear after one and after two generations?

After one generation (20 min): all DNA is hybrid (one band, intermediate density). After two generations (40 min): half the DNA is hybrid and half is light, giving two bands. The heavy 15N strands are never destroyed, they are just diluted into more molecules.

⚠️ The NEET trap
The experimental proof for semiconservative replication was first shown in a plant.
It was first shown in a bacterium, Escherichia coli (Meselson and Stahl, 1958). It was demonstrated in plants like Vicia faba only later.
🧠 First proof = E. coli (a Bacterium). Plants (Taylor) came AFTER. NEET 2018 marked 'Plant' as the trap and 'Bacterium' as correct.

Real NEET questions

NEET 2018

The experimental proof for semiconservative replication of DNA was first shown in a

A · Plant
B · Bacterium
C · Fungus
D · Virus
Solution: Meselson and Stahl proved semiconservative replication in 1958 using the bacterium Escherichia coli. It was shown in higher organisms such as plants only later, so the first proof was in a bacterium.
NEET 2022

Ten E. coli cells with 15N-dsDNA are incubated in a medium containing 14N nucleotides. After 60 minutes, how many E. coli cells will have DNA totally free from 15N?

A · 20 cells
B · 40 cells
C · 60 cells
D · 80 cells
Solution: E. coli divides every 20 minutes, so in 60 minutes there are 3 divisions: 10 to 20 to 40 to 80 cells. Because replication is semiconservative, the 10 original cells had 20 heavy 15N strands, which are conserved and end up in 20 different cells. So 80 minus 20 = 60 cells have DNA totally free of 15N.
NEET 2024

Match List I with List II. A. Frederick Griffith B. Francois Jacob and Jacque Monod C. Har Gobind Khorana D. Meselson and Stahl — I. Genetic code II. Semi-conservative mode of DNA replication III. Transformation IV. Lac operon

A · A-III, B-IV, C-I, D-II
B · A-II, B-III, C-IV, D-I
C · A-IV, B-I, C-II, D-III
D · A-III, B-II, C-I, D-IV
Solution: Griffith = Transformation (III), Jacob and Monod = Lac operon (IV), Khorana = Genetic code (I), Meselson and Stahl = Semi-conservative replication (II). This gives A-III, B-IV, C-I, D-II.

Solved Molecular Basis of Inheritance NEET PYQs

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Frequently asked

In which year and organism was the experiment done?

Matthew Meselson and Franklin Stahl performed it in 1958 using the bacterium Escherichia coli (E. coli).

Is 15N radioactive?

No. 15N is a stable heavy isotope of nitrogen, not a radioactive one. It only makes the DNA heavier so it can be separated by density.

What technique separated the DNA?

Density gradient centrifugation using cesium chloride (CsCl). DNA forms bands based on its weight (density).

Why is one hybrid band after the first generation so important?

A single hybrid band rules out conservative replication (which would give two separate bands, heavy and light). It confirms each daughter DNA has one old and one new strand, which is semiconservative.

How is this different from Taylor's experiment?

Meselson and Stahl used 15N/14N in E. coli DNA. Taylor used radioactive tritiated (3H) thymidine in the plant Vicia faba to prove chromosomes replicate semiconservatively.