Inner vs Outer Orbital Complexes and Magnetic Behaviour

Chemistry · Coordination Compounds · NEET

An inner orbital complex uses the metal's inner 3d orbitals for bonding (d2sp3 hybridisation), so electrons pair up and it is usually low spin with few or no unpaired electrons. An outer orbital complex uses outer 4d orbitals (sp3d2 hybridisation), so electrons stay unpaired and it is high spin and more paramagnetic. Memory hook: "Inner = d2sp3 = strong field = paired = less magnetic; Outer = sp3d2 = weak field = unpaired = more magnetic."
Octahedral Co3+ (d6): Inner vs Outer OrbitalINNER: [Co(NH3)6]3+strong field NH3 to d2sp3up downup downup downt2g (paired)eg (empty)0 unpaired to LOW SPINDIAMAGNETICOUTER: [CoF6]3-weak field F- to sp3d2up dnupupupupt2geg4 unpaired to HIGH SPINPARAMAGNETICSame metal, same octahedral shape, ligand decides magnetism
Same Co3+ d6 metal in an octahedral field: strong-field NH3 pairs electrons (inner d2sp3, low spin, diamagnetic) while weak-field F- keeps them unpaired (outer sp3d2, high spin, paramagnetic).

Your doubts, answered

What is the difference between an inner orbital and an outer orbital complex?

An inner orbital complex uses the metal's inner (n-1)d orbitals, for example the 3d orbitals of a first-row metal, for hybridisation. This gives d2sp3 hybridisation. An outer orbital complex uses the outer nd orbitals, for example 4d, giving sp3d2 hybridisation. Both are octahedral in shape, but they differ in which d orbitals bond and therefore in how many unpaired electrons remain.

Is d2sp3 inner or outer orbital, and sp3d2?

d2sp3 is the INNER orbital complex because the two d orbitals used come BEFORE the s and p (they are the inner 3d orbitals). sp3d2 is the OUTER orbital complex because the two d orbitals come AFTER the s and p (they are the outer 4d orbitals). Easy rule: if 'd' is written first (d2sp3), it is inner; if 'd' is written last (sp3d2), it is outer.

How do I know if a complex is inner or outer orbital?

Look at the ligand. Strong-field ligands (CN-, CO, NH3, en) force electrons to pair up in the inner 3d orbitals, freeing them for d2sp3 bonding, so you get an INNER orbital, low-spin complex. Weak-field ligands (F-, Cl-, H2O) do not force pairing, so the metal must use outer 4d orbitals for sp3d2 bonding, giving an OUTER orbital, high-spin complex. This is why for NEET you must remember the spectrochemical series order.

Why is [Co(NH3)6]3+ diamagnetic but [CoF6]3- is paramagnetic?

In both, cobalt is Co3+ (a d6 ion) and both are octahedral. NH3 is a strong-field ligand, so all six d electrons pair up in the inner 3d orbitals: t2g6 eg0, zero unpaired electrons, so it is a low-spin d2sp3 inner orbital complex and diamagnetic. F- is a weak-field ligand, so the electrons stay spread out: t2g4 eg2, four unpaired electrons, making it a high-spin sp3d2 outer orbital complex and paramagnetic. Same metal, same shape, different ligand strength.

Does inner orbital always mean zero unpaired electrons?

No. Inner orbital just means the inner 3d orbitals are used (d2sp3). The number of unpaired electrons depends on the d electron count. For example, [Co(NH3)6]3+ (d6) is inner and has 0 unpaired electrons, but [Mn(CN)6]3- (d4) is also inner (d2sp3) yet still keeps 2 unpaired electrons. So an inner orbital complex can still be paramagnetic, just with fewer unpaired electrons than the outer version.

How is magnetic behaviour connected to inner vs outer orbital?

More unpaired electrons means more paramagnetic (larger magnetic moment). Inner orbital complexes force pairing, so they usually have fewer unpaired electrons and are less magnetic or diamagnetic. Outer orbital complexes keep electrons unpaired, so they have more unpaired electrons and are more paramagnetic. To get the actual value you count the unpaired electrons and put them into the spin-only formula.

⚠️ The NEET trap
Thinking that because [Co(NH3)6]3+ and [CoF6]3- are both octahedral with the same Co3+ metal, they must have the same magnetic behaviour.
Same metal and same shape do NOT mean same magnetism. NH3 is strong field, so [Co(NH3)6]3+ is inner orbital (d2sp3), low spin, 0 unpaired, diamagnetic. F- is weak field, so [CoF6]3- is outer orbital (sp3d2), high spin, 4 unpaired, paramagnetic.
🧠 Geometry tells you the shape; the LIGAND tells you the magnetism. Always check the ligand's field strength first.

Real NEET questions

NEET 2024

Statement I: Both [Co(NH3)6]3+ and [CoF6]3- complexes are octahedral but differ in their magnetic behaviour. Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3- is paramagnetic. In the light of the above statements, choose the correct answer.

A · Both Statement I and Statement II are false.
B · Statement I is true but Statement II is false.
C · Statement I is false but Statement II is true.
D · Both Statement I and Statement II are true.
Solution: In both complexes cobalt is Co3+, a d6 ion, and both are octahedral. In [Co(NH3)6]3+, NH3 is a strong-field ligand, so the splitting energy is greater than the pairing energy and all six electrons pair up: t2g6 eg0, 0 unpaired, low-spin inner orbital (d2sp3), diamagnetic. In [CoF6]3-, F- is a weak-field ligand, so electrons stay unpaired: t2g4 eg2, 4 unpaired, high-spin outer orbital (sp3d2), paramagnetic. So both are octahedral but differ in magnetic behaviour (Statement I true) and the specific assignment is correct too (Statement II true). Answer: D.
NEET 2017

Pick out the correct statement with respect to [Mn(CN)6]3-.

A · It is sp3d2 hybridised and octahedral
B · It is sp3d2 hybridised and tetrahedral
C · It is d2sp3 hybridised and octahedral
D · It is dsp2 hybridised and square planar
Solution: Each CN- is -1 and there are 6, giving ligand charge -6. For an overall -3 ion, Mn is +3, so Mn(III) is d4. CN- is a strong-field ligand, so it forces the d4 electrons to pair up, vacating two inner 3d orbitals. These two 3d orbitals plus 4s and three 4p give d2sp3 hybridisation, which is an INNER orbital, octahedral, low-spin complex (still 2 unpaired electrons). Answer: C.
NEET 2018

The geometry and magnetic behaviour of the complex [Ni(CO)4] are:

A · Square planar geometry and paramagnetic
B · Tetrahedral geometry and diamagnetic
C · Square planar geometry and diamagnetic
D · Tetrahedral geometry and paramagnetic
Solution: CO is neutral, so Ni is in the 0 oxidation state: Ni(0). Ni is [Ar] 3d8 4s2; under strong-field CO the 4s electrons move into 3d, giving 3d10 4s0. With a filled 3d10 set, all electrons are paired, so the complex is diamagnetic. The empty 4s and three 4p orbitals hybridise as sp3, giving tetrahedral geometry (note: 4-coordinate, so sp3 not inner d2sp3). Answer: B.

Solved Coordination Compounds NEET PYQs

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Frequently asked

What is an inner orbital complex in simple words?

It is an octahedral complex where the metal uses its inner (n-1)d orbitals, such as 3d, for bonding. This happens with strong-field ligands that pair up the electrons. The hybridisation is d2sp3 and the complex is usually low spin.

Which hybridisation belongs to an outer orbital complex?

sp3d2. Here the two d orbitals used are the OUTER nd orbitals, for example 4d. Outer orbital complexes form with weak-field ligands and are high spin with more unpaired electrons.

Are inner orbital complexes always low spin?

Yes, for octahedral complexes inner orbital always means low spin, because pairing has occurred to free the inner d orbitals. Outer orbital always means high spin. But low spin does not always mean zero unpaired electrons; it just means the maximum possible pairing for that ligand.

Why does this topic matter for NEET?

NEET regularly asks you to compare two octahedral complexes of the same metal and decide which is paramagnetic or diamagnetic, or to give the hybridisation (d2sp3 vs sp3d2). Knowing strong-field vs weak-field ligands lets you answer these directly. It also connects to the spin-only magnetic moment formula, a very common numerical question.

How do I quickly decide inner or outer for an exam question?

Step 1: find the metal oxidation state and its d-electron count. Step 2: check the ligand. Strong field (CN-, CO, NH3, NO2-, en) means inner orbital, d2sp3, low spin. Weak field (F-, Cl-, Br-, H2O, OH-) means outer orbital, sp3d2, high spin. Step 3: count unpaired electrons and, if asked, use the spin-only formula.