Oxidation State of Chromium in CrO5 (Why It Is +6, Not +10)

Chemistry · D And F Block Elements · NEET

The oxidation state of chromium in CrO5 is +6. CrO5 is not made of five normal oxide ions. Its real structure is CrO(O2)2: it has one double-bonded oxygen (O with charge -2) and two peroxide links (O2 with total charge -2 each), so the oxygens add up to only -6, giving Cr = +6. Memory hook: "CrO5 = one oxo + two peroxo = butterfly shape, so Cr stays at its normal max +6."
CrO5 = CrO(O2)2 → Cr is +6, not +10Cr(+6)Ooxo O = -2OOOO2 peroxoO2 links= -2 eachSum of O= -6Cr = +6
CrO5 has a butterfly structure CrO(O2)2: one oxo oxygen (-2) plus two peroxide O2 links (-2 each) make the oxygen total only -6, so chromium is +6, not +10.

Your doubts, answered

Why do I get +10 when I calculate the oxidation state of Cr in CrO5?

You get +10 only if you wrongly treat all five oxygens as normal oxide ions (each -2). That gives x + 5(-2) = 0, so x = +10. But +10 is impossible for chromium, because its highest possible oxidation state is +6 (it only has 6 electrons in 3d and 4s to lose). So the -2 rule cannot apply to all oxygens here. This is a signal that CrO5 must contain peroxide oxygens.

What is the real structure of CrO5?

CrO5 is written more correctly as CrO(O2)2. It has one oxo oxygen (a normal O double-bonded to Cr, charge -2) and two peroxo groups (two O-O linkages, each group is O2 with charge -2). Its shape is often called a 'butterfly' structure. So there are not five separate -2 oxide ions; there is 1 oxo oxygen plus 4 oxygens that are joined in pairs as peroxides.

What is the oxidation state of oxygen in a peroxide?

In a normal oxide, oxygen is -2. But in a peroxide the two oxygens share a bond (O-O), so each oxygen is only -1. In CrO5 the four peroxo oxygens are -1 each (total -4), and the one oxo oxygen is -2. Adding gives -6 from oxygen. This is the key NEET fact that changes the answer from +10 to +6.

How do I actually calculate Cr in CrO5 step by step?

Let Cr = x. Method 1 (by peroxo groups): 1 oxo oxygen = -2, and 2 peroxide groups = 2 x (-2) = -4. So x + (-2) + (-4) = 0, giving x = +6. Method 2 (by each atom): 1 oxo oxygen = -2, four peroxo oxygens = 4 x (-1) = -4. So x + (-2) + (-4) = 0, giving x = +6. Both methods give Cr = +6.

Is CrO5 the blue compound formed in the chromium peroxide test?

Yes. When acidified potassium dichromate (K2Cr2O7) is treated with hydrogen peroxide (H2O2), it forms a deep blue CrO5 (chromium peroxide). This blue colour is a common lab test for chromate/dichromate. Even though a peroxide reagent (H2O2) is used, the chromium stays at +6 because the peroxide oxygens carry the extra reduced charge, not the metal.

⚠️ The NEET trap
All five O atoms are -2, so x + 5(-2) = 0 gives Cr = +10 (or the option +12).
CrO5 = CrO(O2)2 has two peroxide (O2^2-) links, so oxygen totals only -6, giving Cr = +6.
🧠 If you ever get an oxidation state above +6 for a transition metal, STOP. It means there is a peroxide or O-O bond. Chromium can never go above +6.

Real NEET questions

NEET 2019

The oxidation state of Cr in CrO5 is:

A · (a) -6
B · (b) +12
C · (c) +6
D · (d) +4
Solution: CrO5 is chromium peroxide, and its correct structure is CrO(O2)2: one oxo oxygen (O with charge -2) and two peroxo linkages (each O2 group has charge -2), not five normal oxide ions. Let Cr = x. Then x + (-2) + 2(-2) = 0, so x + (-2) + (-4) = 0, giving x = +6. If you wrongly treat all five oxygens as -2 you get the impossible value +10 (shown as +12 in the trap option). Recognising the two peroxide O2^2- links gives the correct answer Cr = +6. Answer: (c).

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Frequently asked

What is the oxidation state of chromium in CrO5?

It is +6. CrO5 has the structure CrO(O2)2 with one oxo oxygen (-2) and two peroxide links (each -2 in total), so the oxygens add to -6 and Cr comes out as +6.

Why is it not +10?

+10 comes from wrongly assuming all five oxygens are normal oxide ions (-2 each). CrO5 actually has peroxide oxygens (-1 each), so the total oxygen charge is only -6, not -10. Also, chromium can never reach +10; its maximum is +6.

How many peroxide bonds are there in CrO5?

There are two peroxide (O-O) linkages. Together with one double-bonded oxo oxygen, that accounts for all five oxygen atoms (1 oxo + 4 peroxo).

How is CrO5 formed?

CrO5 (blue) is formed when acidified potassium dichromate reacts with hydrogen peroxide (H2O2). This blue colour is used as a test for chromate and dichromate ions.

Why is this important for NEET?

NEET repeatedly tests peroxo species like CrO5 as a 'trick' oxidation-state question. If you remember that Cr cannot exceed +6 and that CrO5 has peroxide links, you avoid the common +10/+12 trap and answer in seconds.