NEET 2026 (Phase 1) · ChemistryMagnetismPrevious Year Question

The calculated spin only magnetic moment of \ce{Cr^2+} ion is:

  1. A.(a) $5.92$ BM
  2. B.(b) $2.84$ BM
  3. C.(c) $3.87$ BM
  4. D.(d) $4.90$ BM

Correct Answer

(D) (d) $4.90$ BM

Solution & Explanation

\textbf{Answer:} (d) $4.90$ BM. \textbf{Solution:} \ce{Cr^2+} has the configuration \ce{[Ar] 3d^4}, so it has $n = 4$ unpaired electrons. Using the spin-only formula: $\mu = \sqrt{n(n+2)} = \sqrt{4(4+2)} = \sqrt{24} = 4.90$ BM. Hence option (d) is correct.

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