Electrolysis Calculations: Charge, Moles of Electrons and Mass Deposited

Chemistry · Electrochemistry · NEET

To solve any electrolysis sum, follow one chain: charge Q = current × time (Q = I × t). Then divide Q by 96500 to get moles of electrons, and use the electrode reaction to convert electrons into moles (and mass) of the product. Memory hook: "I-t, then over 96500, then use the n." One mole of electrons is one Faraday = 96500 coulombs.
Electrolysis Calculation ChainCharge QQ = I × tMoles of e⁻= Q / 96500Moles product= mol e⁻ / nMass× molar massn = electrons per atom (Cu²⁺:2, Ag⁺:1, Al³⁺:3)1 mole electrons = 1 Faraday = 96500 C
The four-step electrolysis chain: charge Q = It, then Q ÷ 96500 gives moles of electrons, dividing by n gives moles of product, and multiplying by molar mass gives the mass deposited.

Your doubts, answered

What is the exact order of steps to find mass deposited in electrolysis?

Always use the same 4-step chain. Step 1: find charge Q = I × t (current in amperes, time in seconds). Step 2: moles of electrons = Q / 96500. Step 3: use the electrode reaction to find moles of product (divide electrons by n, the electrons needed per atom). Step 4: mass = moles of product × molar mass. Never skip converting time to seconds first.

Why do we divide charge by 96500?

96500 coulombs is the charge carried by 1 mole of electrons. This number is the Faraday constant (NCERT uses 96487, but NEET usually rounds to 96500 or 96000). So dividing the total charge Q by 96500 tells you how many moles of electrons flowed. It is just a unit conversion: coulombs to moles of electrons.

How do I know the value of n (electrons per atom)?

Look at the ion's charge in the electrode half-reaction. Cu²⁺ + 2e⁻ → Cu needs n = 2. Ag⁺ + e⁻ → Ag needs n = 1. Al³⁺ + 3e⁻ → Al needs n = 3. For chlorine at the anode, 2Cl⁻ → Cl₂ + 2e⁻, so 1 mole of Cl₂ gas needs 2 moles of electrons. n is simply the number of electrons in the balanced half-reaction.

What is the difference between moles of electrons and moles of product?

They are not the same. Moles of electrons come straight from Q / 96500. Moles of product = moles of electrons ÷ n. Example: if 2 moles of electrons pass and you deposit Cu (n = 2), you get only 1 mole of Cu. Students lose marks by treating electrons and metal atoms as equal. Always divide by n.

How do I find time if the question gives moles of product instead?

Reverse the chain. Start from moles of product, multiply by n to get moles of electrons, multiply by 96500 to get charge Q, then use t = Q / I. This is exactly the 2016 NEET chlorine question: 0.10 mol Cl₂ needs 0.10 × 2 × 96500 = 19300 C, and t = 19300 / 3 ≈ 6433 s ≈ 110 minutes.

How do I count the actual number of electrons (not moles)?

First find total charge Q = I × t. Then divide by the charge of one electron (1.6 × 10⁻¹⁹ C), not by 96500. Number of electrons = Q / (1.6 × 10⁻¹⁹). Use 96500 only when you want moles of electrons. Read the question: 'number of electrons' means use 1.6 × 10⁻¹⁹.

⚠️ The NEET trap
Treating moles of electrons as equal to moles of metal, so students forget to divide by n. For chlorine they also forget that 1 mole of Cl₂ needs 2 moles of electrons.
In the 2016 NEET question, 0.10 mol Cl₂ needs 0.10 × 2 × 96500 = 19300 C. Then t = 19300 / 3 ≈ 6433 s ≈ 110 minutes (option B), not 55 minutes.
🧠 The '55 minutes' trap answer is what you get if you forget the ×2 for Cl₂. Always multiply moles of product by n first.

Real NEET questions

NEET 2016 Phase 2

During the electrolysis of molten sodium chloride, the time required to produce 0.10 mol of chlorine gas using a current of 3 amperes is

A · 55 minutes
B · 110 minutes
C · 220 minutes
D · 330 minutes
Solution: At the anode chlorine forms: 2Cl⁻ → Cl₂ + 2e⁻. So 1 mole of Cl₂ needs 2 moles of electrons, meaning 2 × 96500 C. For 0.10 mol Cl₂: Q = 0.10 × 2 × 96500 = 19300 C. Now Q = I × t, so t = Q / I = 19300 / 3 ≈ 6433 s. Convert to minutes: 6433 / 60 ≈ 110 minutes. Answer: B.
NEET 2016 Phase 2

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60 × 10⁻¹⁹ C)

A · 6 × 10²³
B · 6 × 10²⁰
C · 3.75 × 10²⁰
D · 7.48 × 10²³
Solution: Step 1: charge Q = I × t = 1 × 60 = 60 C. Step 2: the question asks for the NUMBER of electrons, not moles, so divide by the charge of one electron: n = Q / e = 60 / (1.60 × 10⁻¹⁹) = 3.75 × 10²⁰ electrons. Answer: C. Note: divide by 96500 only if it had asked for moles of electrons.

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Frequently asked

What is one Faraday equal to?

One Faraday is the charge of 1 mole of electrons. Its value is 96487 C/mol in NCERT, usually rounded to 96500 C/mol in NEET numericals.

Which formula links current and time to charge?

Q = I × t, where Q is charge in coulombs, I is current in amperes, and t is time in seconds. Always convert minutes or hours to seconds first.

How is mass deposited related to charge?

By Faraday's first law, mass deposited is directly proportional to the charge passed. In steps: mass = (Q / 96500) ÷ n × molar mass, where n is electrons per atom.

Do I use 96500 or 1.6 × 10⁻¹⁹ when counting electrons?

Use 96500 when the answer should be in moles of electrons. Use 1.6 × 10⁻¹⁹ C when the question asks for the actual number of individual electrons.

Why does this topic matter for NEET?

Electrolysis numericals appear almost every year and are quick, guaranteed marks if you follow the Q = It chain. They test unit conversion and the electrode half-reaction, both easy to master.