Why O and F Have Less Negative Electron Gain Enthalpy Than S and Cl

Chemistry · Periodic Classification Of Properties · NEET

Oxygen and fluorine are very small atoms, so their outer 2p shell is tiny and already packed with electrons. When you add one more electron, it feels strong push-back (repulsion) from the electrons already crammed in that small space. Sulphur and chlorine are bigger, so their 3p shell has more room and the new electron fits comfortably, releasing more energy. Memory hook: "small box, big squeeze" — the small 2p box squeezes the new electron, so less energy is released.
Small 2p shell squeezes the new electronFTiny 2p: crowded, strong repulsionLess negative EGH (-328)ClRoomy 3p: electron fits easilyMore negative EGH (-349)new e-
Fluorine's small 2p shell is crowded, so the incoming electron (blue) is repelled and less energy is released. Chlorine's larger 3p shell has room, so it accepts the electron more easily and releases more energy, making Cl's electron gain enthalpy more negative than F's.

Your doubts, answered

Why does fluorine have less negative electron gain enthalpy than chlorine, when F is above Cl?

Normally, going down a group, electron gain enthalpy becomes less negative because the atom gets bigger and the nucleus pulls the new electron less. So you would expect F (top) to be the most negative. But F breaks this rule. F is extremely small, so its 2p shell is very compact and already crowded with electrons. When one more electron is added, it faces strong repulsion in that tiny space. Cl is bigger, its 3p shell is roomier, so the added electron settles more easily and releases more energy. Result: Cl (-349 kJ/mol) is MORE negative than F (-328 kJ/mol).

Is oxygen or sulphur electron gain enthalpy more negative?

Sulphur is more negative. O has electron gain enthalpy about -141 kJ/mol, while S is about -200 kJ/mol. Even though O is higher up (and 'should' hold an electron more tightly), its small 2p shell crowds the incoming electron and repels it. S has a larger 3p shell with more room, so it accepts the electron more happily and releases more energy. This is the same reason F is less negative than Cl.

What exactly causes the extra repulsion in O and F?

The added electron goes into the 2p subshell. In O and F, the 2p subshell is small and already holds several electrons packed close together. Electrons all carry negative charge and push each other away. In such a small region, this electron-electron repulsion is very strong. It partly cancels the pull from the nucleus, so less net energy is released. In S and Cl the electron enters the larger 3p subshell where electrons are more spread out, so repulsion is weaker.

So which element in period 3 has the MOST negative electron gain enthalpy?

Chlorine. NCERT states clearly: chlorine has the most negative electron gain enthalpy of all elements. This is because Cl has a strong nuclear pull AND a roomy 3p shell, so it adds an electron very easily. Fluorine, despite being more electronegative, is not the most negative because of the small-shell repulsion. Watch out: NEET often tries to trick you into picking F as 'most negative' — the correct answer is Cl.

Does this mean fluorine is less reactive or less electronegative than chlorine?

No. Electron gain enthalpy and electronegativity are different things. Fluorine is still the MOST electronegative element (Pauling value 4.0) and is very reactive. Electron gain enthalpy is the energy released when one gas-phase atom gains one electron; electronegativity is the tendency of a bonded atom to pull shared electrons. F wins on electronegativity but loses to Cl on electron gain enthalpy because of its cramped 2p shell. Do not mix the two up.

Is this rule only for group 16 and 17, or does it happen everywhere?

It is a general trend for period-2 versus period-3 elements. The first member of a p-block group (N, O, F) is unusually small, so its electron gain enthalpy is less negative than the second member (P, S, Cl). After the first two members, the normal 'less negative down the group' trend takes over (Cl > Br > I). So the anomaly is specifically the 2nd-period element being smaller/less negative than the 3rd-period one right below it.

⚠️ The NEET trap
Fluorine has the most negative electron gain enthalpy because it is the most electronegative element.
Chlorine has the most negative electron gain enthalpy. Fluorine's tiny 2p shell causes strong electron-electron repulsion, so its electron gain enthalpy is LESS negative than chlorine's, even though F is the most electronegative.
🧠 Most electronegative (F) is NOT the same as most negative electron gain enthalpy (Cl). NEET loves this swap.

Real NEET questions

ReNEET 2026

Among the following, the correct trend in electron gain enthalpy (most negative first) is:

A · F > Cl > Br > I
B · Br > Cl > F > I
C · Cl > F > Br > I
D · I > Br > Cl > F
Solution: Down group 17, electron gain enthalpy generally becomes less negative. But fluorine is anomalous: its very small size makes the 2p subshell compact, causing strong inter-electronic repulsion when an electron is added. This makes F's electron gain enthalpy LESS negative than chlorine's. So the magnitude order is Cl > F > Br > I. Chlorine, not fluorine, is the most negative. Answer: (C).
NEET 2016 Phase 1

In which option does the order NOT agree with the property indicated? (choose the wrong one) — one option reads: I < Br < Cl < F (increasing electron gain enthalpy).

A · Al3+ < Mg2+ < Na+ < F- (increasing ionic size)
B · B < C < N < O (increasing first ionization enthalpy)
C · I < Br < Cl < F (increasing electron gain enthalpy)
D · Li < Na < K < Rb (increasing metallic radius)
Solution: The officially wrong arrangement is (B): due to N's stable half-filled 2p3, the correct first ionization enthalpy order is B < C < O < N, not B < C < N < O. Note on option (C): the given order I < Br < Cl < F is what many textbooks list for the simple down-group trend, but because of F's small-shell anomaly the true magnitude order is I < Br < F < Cl (Cl most negative). NEET here treated (C) as acceptable and marked (B) as the answer, so read every option carefully and remember the F/Cl anomaly.

Solved Periodic Classification Of Properties NEET PYQs

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Frequently asked

What are the actual electron gain enthalpy values for O, F, S, Cl?

Approximate values: O about -141 kJ/mol, S about -200 kJ/mol, F about -328 kJ/mol, Cl about -349 kJ/mol. In both pairs the period-3 element (S, Cl) is more negative than the period-2 element (O, F).

Why is chlorine's electron gain enthalpy the most negative of all elements?

Chlorine has a strong effective nuclear charge to pull in an electron, plus a spacious 3p shell that avoids the crowding problem faced by fluorine. This combination makes it release the most energy on gaining an electron.

Does the same anomaly appear in ionization enthalpy?

The idea of small-size effects appears in many period-2 anomalies, but the specific 'less negative electron gain enthalpy' point is mainly discussed for O/F versus S/Cl. Ionization enthalpy has its own anomalies (like N being higher than O due to half-filled stability).

Is fluorine still a good oxidising agent despite this?

Yes. Fluorine is the strongest oxidising agent among halogens. Electron gain enthalpy in the gas phase is only one factor; in solution, F's small size gives a very high hydration energy, so it is still extremely reactive.

How should I answer this in a NEET MCQ quickly?

Remember one line: Cl > F for electron gain enthalpy magnitude, and S > O too. The tiny 2p shell of the top element repels the extra electron. If an option calls F the 'most negative', it is a trap.