IUPAC Provisional Names and Three-Letter Symbols for Elements (Z > 100)

Chemistry · Periodic Classification Of Properties · NEET

For new elements with atomic number greater than 100, IUPAC gives a temporary name by spelling out each digit of the atomic number using number roots (nil=0, un=1, bi=2, tri=3, quad=4, pent=5, hex=6, sept=7, oct=8, enn=9), then adding "-ium" at the end. The three-letter symbol is just the first letter of each root. Memory hook: "Number In Big Table, Quietly Print Her Special Owl Eggs" gives nil-un-bi-tri-quad-pent-hex-sept-oct-enn.
Building an IUPAC Provisional Name: Z = 105105each digit becomes a rootunnilpent+ ium =unnilpentiumsymbol: UnpRoots: nil0 un1 bi2 tri3 quad4 pent5 hex6 sept7 oct8 enn9
Three steps to name element 105: split the atomic number into digits, swap each digit for its root (un, nil, pent), then add -ium. The symbol Unp comes from the first letter of each root.

Your doubts, answered

How do I write the IUPAC provisional name for any element with atomic number more than 100?

Follow three simple steps. Step 1: write the atomic number digit by digit. Step 2: replace each digit with its root word (nil=0, un=1, bi=2, tri=3, quad=4, pent=5, hex=6, sept=7, oct=8, enn=9) and join them in order. Step 3: add '-ium' at the end. Example: Z = 104 is 1-0-4, so un + nil + quad + ium = unnilquadium (symbol Unq). This matters for NEET because at least one question on element naming appears almost every year.

What are the number roots I must memorize for IUPAC naming?

There are ten roots, one for each digit 0 to 9: nil (0), un (1), bi (2), tri (3), quad (4), pent (5), hex (6), sept (7), oct (8), enn (9). You spell the atomic number using these roots in the same order the digits appear. This is the single most tested fact of this topic, so learn the roots cold.

How is the three-letter symbol made from the name?

Take the FIRST letter of each root and capitalise only the first one. For Z = 105, the roots are un-nil-pent, so the symbol is Unp. For Z = 120, roots are un-bi-nil, symbol is Ubn. The symbol always has as many letters as the atomic number has digits (three letters for three-digit atomic numbers).

Why does the name always end in -ium even for elements that are not metals?

The '-ium' suffix is a fixed rule of the systematic (provisional) naming system, not a claim about the element's metallic character. Every provisional name of an element with Z > 100 ends in -ium, no matter what block it is in. So do not remove or change the ending.

What is the difference between the provisional name and the permanent (official) name?

The provisional name (like unnilunium for Z=101) is a temporary placeholder used until the element's discovery is confirmed and a permanent name is agreed. Once IUPAC ratifies the discovery, the discoverer suggests a permanent name (like mendelevium for Z=101) and a normal one- or two-letter symbol (Md). NEET loves to match provisional names with official names, so learn a few pairs.

How do I decode a provisional name back into an atomic number?

Split the name into its roots and read each root as a digit. Example: 'ununennium' splits into un-un-enn-ium = 1-1-9 = atomic number 119. Reverse the process you use to build a name. This is exactly how NEET 2022 asked for Z=119.

⚠️ The NEET trap
Reading Unnilunium as atomic number 111 (because 'un' appears and looks like 1-1-1).
Unnilunium = un-nil-un = 1-0-1 = atomic number 101 = Mendelevium (Md). The middle root is 'nil' = 0, not another 'un'.
🧠 Read every root separately, left to right. 'nil' hiding in the middle means a zero. Un-nil-un is 1-0-1, never 111 (that would be un-un-un = unununium).

Real NEET questions

2020

Match the following IUPAC provisional names with their IUPAC official names. Column-I: (a) Unnilunium (b) Unniltrium (c) Unnilhexium (d) Unununnium. Column-II: (i) Mendelevium (ii) Lawrencium (iii) Seaborgium (iv) Darmstadtium. Which one of the following is correct?

A · (c)-(iii)
B · (d)-(iv)
C · (a)-(i)
D · (b)-(ii)
Solution: Decode each provisional name using the roots (un=1, nil=0, tri=3, hex=6). Unnilunium = 1-0-1 = 101 = Mendelevium (Md), so (a)-(i) is correct. Check the others: Unniltrium = 1-0-3 = 103 = Lawrencium (Lr), so (ii) matches (b), not the same as option D's claim style. Unnilhexium = 1-0-6 = 106 = Seaborgium (Sg). Unununnium = 1-1-1 = 111 = Roentgenium (Rg), NOT Darmstadtium (which is 110). Among the single-pair options given, only (a)-(i) is correct, so the answer is C.
2022

The IUPAC name of an element with atomic number 119 is:

A · ununennium
B · unnilennium
C · unununnium
D · ununoctium
Solution: Write 119 digit by digit: 1-1-9. Roots: 1 = un, 1 = un, 9 = enn. Join them and add -ium: un-un-enn-ium = ununennium (symbol Uue). Distractors: unnilennium = 1-0-9 = 109, unununnium = 1-1-1 = 111, ununoctium = 1-1-8 = 118. So the correct answer is A.

Solved Periodic Classification Of Properties NEET PYQs

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Frequently asked

Is IUPAC provisional naming asked in NEET?

Yes. Direct questions asking the provisional name of a given atomic number (like Z=119 in NEET 2022) or matching provisional names with official names (NEET 2020) appear regularly, so this small topic gives easy marks.

What is the provisional name and symbol of element 118?

118 is 1-1-8, so un-un-oct-ium = ununoctium, symbol Uuo. Its permanent name is oganesson (Og).

Do I need to memorize the permanent names too?

Memorize the roots first, as they let you build any provisional name. Then learn a handful of famous permanent-name pairs (101 mendelevium, 103 lawrencium, 106 seaborgium, 111 roentgenium) because matching-type questions use them.

Why does IUPAC use a temporary name at all?

When two labs claim the same new element (for example element 104 was called both Rutherfordium and Kurchatovium), IUPAC needs a neutral placeholder name based only on the atomic number until the real discoverer is confirmed. This avoids naming fights.

Can the same root repeat in one name?

Yes. Roots repeat whenever a digit repeats. For 111 you get un-un-un = unununium (Uuu). Just read each root in order.