Oxidation States in KO2 (Potassium Superoxide)

Chemistry · Redox Equilibrium · NEET

In KO2 (potassium superoxide), potassium is +1 and each oxygen is -1/2 (the O2^- superoxide ion has one -1 charge shared over two oxygen atoms). Oxygen is NOT the usual -2 here. Memory hook: "Super-half" — Superoxide gives oxygen a half charge, -1/2.
Oxygen oxidation state: Oxide vs Peroxide vs SuperoxideOxidee.g. Na2O, MgOion: O^2-O = -2Peroxidee.g. Na2O2, H2O2ion: O2^2-O = -1Superoxidee.g. KO2, RbO2ion: O2^-O = -1/2Metal (K, Na) stays +1 in all three — only oxygen changes
Oxygen's oxidation state depends on the ion: -2 in oxides, -1 in peroxides, and -1/2 in the superoxide KO2, while potassium remains +1 throughout.

Your doubts, answered

Why is oxygen -1/2 in KO2 and not -2?

KO2 is a superoxide, built from the superoxide ion O2^- (not O^2-). Potassium is a Group 1 metal and is fixed at +1. To make the compound neutral, the two oxygen atoms together must carry -1. So charge per oxygen = -1 divided by 2 = -1/2. Oxygen only takes its normal -2 in simple oxides like Na2O or MgO, not here.

How can an oxidation state be a fraction like -1/2?

Oxidation state is an average charge spread over the atoms of one element in a species. In O2^-, the single extra -1 charge is shared equally by two oxygen atoms, so the average per atom is -1/2. Fractional oxidation states are allowed and just mean the atoms are averaged (same idea appears in Fe3O4 where Fe averages +8/3).

What is the difference between oxide, peroxide and superoxide?

They differ in the oxygen oxidation state. Oxide (like Na2O): O is -2. Peroxide (like Na2O2, H2O2): O is -1, from the O2^2- ion. Superoxide (like KO2): O is -1/2, from the O2^- ion. The metal stays at its normal value (+1 for K/Na) in all three; only the oxygen changes.

Why do heavier alkali metals like K, Rb, Cs form superoxides?

Larger cations (K+, Rb+, Cs+) have low charge density, so they stabilise the large, low-charge superoxide ion O2^-. Small Li+ forms mainly the oxide, Na+ forms the peroxide, while K, Rb and Cs form stable superoxides (KO2, RbO2, CsO2). This is why KO2 exists and is used to release O2 in breathing equipment.

Can I use the shortcut sum = 0 formula for KO2?

Yes, but do not force oxygen to -2. Set K = +1 and let each O = x: (+1) + 2x = 0, so 2x = -1 and x = -1/2. If you wrongly assume O = -2 you would get K = +4, which is impossible for potassium. The trick is to fix the metal (+1) and solve for oxygen, not the reverse.

⚠️ The NEET trap
Assume oxygen is always -2, so for KO2: K + 2(-2) = 0 gives K = +4.
Potassium is a Group 1 metal fixed at +1. KO2 is a superoxide (O2^-), so each O = -1/2 and K stays +1. Oxygen is -2 only in normal oxides.
🧠 Fix the METAL first (+1), then solve oxygen. Never let potassium go to +4 — that is the classic NTA bait.

Real NEET questions

2022

Identify the incorrect statement from the following:

A · Alkali metals react with water to form their hydroxides
B · The oxidation number of K in KO2 is +4
C · Ionisation enthalpy of alkali metals decreases from top to bottom in the group
D · Lithium is the strongest reducing agent among the alkali metals
Solution: KO2 is potassium superoxide. Potassium is a Group 1 metal and is always +1. The superoxide ion O2^- carries an overall -1 charge shared by two oxygens, so each O is -1/2 and K is +1 (not +4). Statements a, c and d are correct alkali-metal properties, so the incorrect one is b.
2025

Consider the compounds KO2, H2O2 and H2SO4. The oxidation states of the underlined elements (K in KO2, O in H2O2, S in H2SO4) respectively are:

A · +1, -2 and +4
B · +4, -4 and +6
C · +1, -1 and +6
D · +2, -2 and +6
Solution: KO2 is a superoxide, so K = +1 (each O = -1/2). H2O2 is a peroxide, so O = -1. In H2SO4: 2(+1) + S + 4(-2) = 0 gives S = +6. So the values are +1, -1 and +6, which is option c.

Solved Redox Equilibrium NEET PYQs

Try the real previous-year questions from this chapter — each with the answer and a full solution.

See all 22 Redox Equilibrium NEET PYQs ›
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Frequently asked

What is the oxidation state of K and O in KO2?

Potassium is +1 and each oxygen is -1/2. KO2 is potassium superoxide, and the O2^- ion holds a -1 charge shared over two oxygen atoms.

Is KO2 a peroxide or a superoxide?

KO2 is a superoxide (contains O2^- with oxygen at -1/2). A peroxide contains O2^2- with oxygen at -1, like Na2O2 and H2O2.

Can potassium ever be +4?

No. Potassium is a Group 1 alkali metal with only one valence electron, so it is always +1 in compounds. A +4 answer for K in KO2 is the deliberate trap.

Why is a -1/2 oxidation state allowed?

Oxidation state is an average charge per atom. The single -1 charge of O2^- is shared equally by two oxygens, giving -1/2 each. Fractions are valid whenever a charge is averaged over identical atoms.

How is KO2 used in real life?

KO2 reacts with CO2 and moisture to release O2, so it is used in breathing masks, submarines and space missions. This is a redox use, but for NEET the key point is K = +1 and O = -1/2.