The E^° values are: Al+/Al = +0.55 V, Tl+/Tl = -0.34 V, Al^3+/Al = -1.66 V and Tl^3+/Tl = +1.26 V. Identify the incorrect statement.

Correct answer: (D) (d) Tl^3+ is a better reducing agent than Tl+.. Answer: (d) Tl^3+ is a better reducing agent than Tl+. Solution: Tl^3+ has a high positive reduction potential (Tl^3+/Tl = +1.26 V) and the Tl^3+/Tl+ couple is strongly oxidising. Hence Tl^3+ readily accepts electrons to form Tl+, so it acts as an oxidising agent, NOT a reducing agent. Statement (d) is therefore incorrect. The other statements are correct: the E^° values make Al+ disproportionate (unstable), Tl+ more stable than Tl^3+, and the more negative Al^3+/Al potential makes Al more electropositive than Tl.

NEET 2023 Phase 2 · ChemistryPrevious Year Question

The $E^{\circ}$ values are: $Al X^{+} / Al$ $= + 0.55$ V, $Tl X^{+} / Tl$ $= - 0.34$ V, $Al X^{3 +} / Al$ $= - 1.66$ V and $Tl X^{3 +} / Tl$ $= + 1.26$ V. Identify the incorrect statement.

Answer: (D) (d) $Tl X^{3 +}$ is a better reducing agent than $Tl X^{+}$ .. \textbf{Answer:} (d) $Tl X^{3 +}$ is a better reducing agent than $Tl X^{+}$ .

A.(a) $Al X^{+}$ is unstable in solution.
B.(b) $Tl$ can be more easily oxidised to $Tl X^{+}$ than to $Tl X^{3 +}$ .
C.(c) $Al$ is more electropositive than $Tl$ .
D.(d) $Tl X^{3 +}$ is a better reducing agent than $Tl X^{+}$ .✓

Correct Answer

(D) (d) $Tl X^{3 +}$ is a better reducing agent than $Tl X^{+}$ .

Solution & Explanation

\textbf{Answer:} (d) $Tl X^{3 +}$ is a better reducing agent than $Tl X^{+}$ . \textbf{Solution:} $Tl X^{3 +}$ has a high positive reduction potential ( $Tl X^{3 +} / Tl = + 1.26$ V) and the $Tl X^{3 +} / Tl X^{+}$ couple is strongly oxidising. Hence $Tl X^{3 +}$ readily accepts electrons to form $Tl X^{+}$ , so it acts as an oxidising agent, NOT a reducing agent. Statement (d) is therefore incorrect. The other statements are correct: the $E^{\circ}$ values make $Al X^{+}$ disproportionate (unstable), $Tl X^{+}$ more stable than $Tl X^{3 +}$ , and the more negative $Al X^{3 +} / Al$ potential makes $Al$ more electropositive than $Tl$ .

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The E∘ values are: AlX+/Al =+0.55 V, TlX+/Tl =−0.34 V, AlX3+/Al =−1.66 V and TlX3+/Tl =+1.26 V. Identify the incorrect statement.

Solution & Explanation

More NEET PYQ solutions

The $E^{\circ}$ values are: $Al X^{+} / Al$ $= + 0.55$ V, $Tl X^{+} / Tl$ $= - 0.34$ V, $Al X^{3 +} / Al$ $= - 1.66$ V and $Tl X^{3 +} / Tl$ $= + 1.26$ V. Identify the incorrect statement.