NEET 2025 · ChemistryAcid acidityPrevious Year Question

The correct order of decreasing acidity of the following aliphatic acids is

  1. A.(A) \ce{HCOOH > CH3COOH > (CH3)2CHCOOH > (CH3)3CCOOH}
  2. B.(B) \ce{HCOOH > (CH3)3CCOOH > (CH3)2CHCOOH > CH3COOH}
  3. C.(C) \ce{(CH3)3CCOOH > (CH3)2CHCOOH > CH3COOH > HCOOH}
  4. D.(D) \ce{CH3COOH > (CH3)2CHCOOH > (CH3)3CCOOH > HCOOH}

Correct Answer

(A) (A) \ce{HCOOH > CH3COOH > (CH3)2CHCOOH > (CH3)3CCOOH}

Solution & Explanation

\textbf{Answer:} (A) \ce{HCOOH > CH3COOH > (CH3)2CHCOOH > (CH3)3CCOOH}. \textbf{Solution:} Electron-donating ($+I$) alkyl groups destabilise the carboxylate anion and reduce acidity. As more or larger alkyl groups are attached near the \ce{-COOH}, the $+I$ effect grows and acid strength falls. With no alkyl group, \ce{HCOOH} is the strongest; acidity then decreases through \ce{CH3COOH} and \ce{(CH3)2CHCOOH} to the weakest \ce{(CH3)3CCOOH}.

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