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NEET 2025 · ChemistryPrevious Year Question

The correct order of decreasing basic strength of the given amines is:

Answer: (A) N-ethylethanamine > ethanamine > N-methylaniline > benzenamine. \textbf{Answer:} (a) \textbf{Solution:} Basicity depends on the electron density available on nitrogen.

  1. A.N-ethylethanamine > ethanamine > N-methylaniline > benzenamine✓
  2. B.Benzenamine > ethanamine > N-methylaniline > N-ethylethanamine
  3. C.N-methylaniline > benzenamine > ethanamine > N-ethylethanamine
  4. D.N-ethylethanamine > ethanamine > benzenamine > N-methylaniline

Correct Answer

(A) N-ethylethanamine > ethanamine > N-methylaniline > benzenamine

Solution & Explanation

\textbf{Answer:} (a) \textbf{Solution:} Basicity depends on the electron density available on nitrogen. Alkyl groups donate by , increasing basicity, so the secondary aliphatic amine N-ethylethanamine (diethylamine) is more basic than primary ethanamine. In aryl amines the nitrogen lone pair is delocalised into the ring ( resonance), lowering basicity; N-methylaniline (whose methyl partly compensates) is more basic than benzenamine (aniline). The overall order is N-ethylethanamine > ethanamine > N-methylaniline > benzenamine.

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