NEET 2025 · ChemistryPrevious Year Question
The correct order of decreasing basic strength of the given amines is:
- A.N-ethylethanamine > ethanamine > N-methylaniline > benzenamine✓
- B.Benzenamine > ethanamine > N-methylaniline > N-ethylethanamine
- C.N-methylaniline > benzenamine > ethanamine > N-ethylethanamine
- D.N-ethylethanamine > ethanamine > benzenamine > N-methylaniline
Correct Answer
(A) N-ethylethanamine > ethanamine > N-methylaniline > benzenamine
Solution & Explanation
\textbf{Answer:} (a) \textbf{Solution:} Basicity depends on the electron density available on nitrogen. Alkyl groups donate by $+I$, increasing basicity, so the secondary aliphatic amine N-ethylethanamine (diethylamine) is more basic than primary ethanamine. In aryl amines the nitrogen lone pair is delocalised into the ring ($-M$ resonance), lowering basicity; N-methylaniline (whose $+I$ methyl partly compensates) is more basic than benzenamine (aniline). The overall order is N-ethylethanamine > ethanamine > N-methylaniline > benzenamine.
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