NEET 2025 · ChemistryPrevious Year Question

Match List I (Mixture) with List II (Method of Separation). List I A. $\ce{CHCl3}$ + $\ce{C6H5NH2}$ B. Crude oil in the petroleum industry C. Glycerol from spent-lye D. Aniline-water List II I. Distillation under reduced pressure II. Steam distillation III. Fractional distillation IV. Simple distillation

  1. A.A-III, B-IV, C-I, D-II
  2. B.A-III, B-IV, C-II, D-I
  3. C.A-IV, B-III, C-I, D-II
  4. D.A-IV, B-III, C-II, D-I

Correct Answer

(C) A-IV, B-III, C-I, D-II

Solution & Explanation

\textbf{Answer:} (c) \textbf{Solution:} Chloroform and aniline differ widely in boiling point, so they are separated by simple distillation (A-IV). The components of crude oil have close, graded boiling points and need fractional distillation (B-III). Glycerol decomposes near its boiling point, so it is separated from spent-lye by distillation under reduced pressure (C-I). Aniline is steam-volatile and immiscible with water, so it is purified by steam distillation (D-II).

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