NEET 2025 · ChemistryPrevious Year Question
Match List I (Mixture) with List II (Method of Separation). List I A. $\ce{CHCl3}$ + $\ce{C6H5NH2}$ B. Crude oil in the petroleum industry C. Glycerol from spent-lye D. Aniline-water List II I. Distillation under reduced pressure II. Steam distillation III. Fractional distillation IV. Simple distillation
- A.A-III, B-IV, C-I, D-II
- B.A-III, B-IV, C-II, D-I
- C.A-IV, B-III, C-I, D-II✓
- D.A-IV, B-III, C-II, D-I
Correct Answer
(C) A-IV, B-III, C-I, D-II
Solution & Explanation
\textbf{Answer:} (c) \textbf{Solution:} Chloroform and aniline differ widely in boiling point, so they are separated by simple distillation (A-IV). The components of crude oil have close, graded boiling points and need fractional distillation (B-III). Glycerol decomposes near its boiling point, so it is separated from spent-lye by distillation under reduced pressure (C-I). Aniline is steam-volatile and immiscible with water, so it is purified by steam distillation (D-II).
🎯
Practice NEET 2025 Chemistry — free, with instant solutions
10,000+ NEET PYQs solved step-by-step, chapter-wise, in the MedicNEET app.
More NEET PYQ solutions
ChemIdentify the suitable reagent for the following conversion: \ce{C6H5COOCH3 -> C6H5CHO} (methyl benzoate to benzaldehyde)ChemThe correct order of decreasing acidity of the following aliphatic acids isChemThe major product of the following reaction is: 4-oxo-4-phenylbutanenitrile \ce{C6H5-CO-CH2-CH2-CN} is treated with (i) \ce{CH3MgBr} (excess) and then (ii) \ce{H3O+}.ChemOut of the following complex compounds, which compound will have the minimum conductance in solution?ChemWhich of the following are paramagnetic? A. \ce{[NiCl4]^2-} B. \ce{Ni(CO)4} C. \ce{[Ni(CN)4]^2-} D. \ce{[Ni(H2O)6]^2+} E. \ce{Ni(PPh3)4}ChemThe correct order of the wavelength of light absorbed by the following complexes is: A. $\ce{[Co(NH3)6]^3+}$ B. $\ce{[Co(CN)6]^3-}$ C. $\ce{[Cu(H2O)4]^2+}$ D. $\ce{[Ti(H2O)6]^3+}$ChemThe correct order of decreasing basic strength of the given amines is: (N-ethylethanamine $=$ \ce{(C2H5)2NH}; ethanamine $=$ \ce{C2H5NH2}; N-methylaniline $=$ \ce{C6H5NH(CH3)}; benzenamine/aniline $=$ \ce{C6H5NH2})ChemPredict the major product $P$ in the following sequence of reactions. The starting material is 1-methylcyclopent-1-ene: (i) \ce{HBr}, benzoyl peroxide; (ii) \ce{KCN}; (iii) \ce{Na(Hg)}/\ce{C2H5OH} $\rightarrow$ $P$ (major). The structures of the options (A)-(D) are shown in the image below:
