Aufbau, Pauli and Hund's Rule: How Electrons Fill Orbitals

Chemistry · Structure Of Atom · NEET

Three rules decide how electrons fill orbitals in an atom. Aufbau says fill the lowest-energy orbital first (use the n+l rule). Pauli says one orbital holds at most 2 electrons, and they must have opposite spins. Hund says when a subshell has equal-energy orbitals (like the three p orbitals), put one electron in each singly, all with the same spin, before any pairing starts. Memory hook: "Build low (Aufbau), pair opposite (Pauli), spread out first (Hund)."
Filling the three 2p orbitals (Nitrogen: 2p³)Hund: one electron each, same spin, before pairing2pₓ2p_y2p_zCorrect: 3 unpaired, all spin up (parallel)wrong (paired too early)Wrong: pairing before all are singly filled
Hund's rule for nitrogen's 2p³: electrons enter the three equal-energy p orbitals one at a time with parallel spins (left, correct) instead of pairing up early (right, wrong). Arrows show electron spin direction; each orbital can hold at most 2 by Pauli.

Your doubts, answered

What is the difference between Aufbau, Pauli and Hund's rule in simple words?

Each rule answers a different question. Aufbau answers WHICH orbital fills first: always the lowest energy one, found using the (n+l) rule. Pauli answers HOW MANY electrons an orbital can hold: at most 2, and they must spin opposite ways. Hund answers HOW to fill orbitals of equal energy: place one electron in each orbital first (all same spin), then start pairing. Think of it as order, then limit, then arrangement.

How does the (n+l) rule decide the filling order?

For any orbital, add its principal quantum number n and azimuthal quantum number l. The orbital with the smaller (n+l) value has lower energy and fills first. If two orbitals have the same (n+l) value, the one with the smaller n fills first. Example: 4s has n+l = 4+0 = 4, and 3d has n+l = 3+2 = 5. Since 4 is smaller, 4s fills before 3d. This is why 4s comes before 3d even though 3 is less than 4.

Which fills first, 4s or 3d?

4s fills first. Using the (n+l) rule: 4s gives 4+0 = 4 and 3d gives 3+2 = 5. Lower (n+l) means lower energy, so 4s (value 4) is filled before 3d (value 5). This is a very common NEET trap because 3 looks smaller than 4, but the rule is about n+l, not just n.

Can two electrons in the same orbital have the same spin?

No. This is the Pauli Exclusion Principle. No two electrons in one atom can have all four quantum numbers the same. Two electrons in the same orbital already share n, l and m (magnetic). So they MUST differ in the fourth one, the spin quantum number: one is +1/2 and the other is -1/2. That is why an orbital holds a maximum of 2 electrons, and they always spin opposite.

Why do electrons go singly into orbitals before pairing up?

This is Hund's rule of maximum multiplicity. When orbitals have the same energy (like the three 2p orbitals), electrons spread out one per orbital, all with parallel (same) spin, before any pairing. They do this because electrons repel each other. Staying in separate orbitals keeps them farther apart, which lowers energy and gives extra stability from something called exchange energy. So nitrogen is 2p to the power one in each of px, py, pz, not two electrons in one p orbital.

What does 'maximum multiplicity' mean in Hund's rule?

Multiplicity is linked to the number of unpaired electrons with parallel spin. 'Maximum multiplicity' means the correct ground-state arrangement is the one with the greatest number of unpaired electrons of the same spin. Filling each equal-energy orbital singly first gives the most unpaired electrons, so that arrangement is chosen. This matters in NEET for counting unpaired electrons and calculating magnetic moment.

Do these rules ever break? What about Cr and Cu?

The rules give the ground-state configuration, but a few elements look like exceptions because half-filled and fully-filled subshells are extra stable. Chromium is 3d to the power 5, 4s to the power 1 (not 3d to the power 4, 4s to the power 2) and copper is 3d to the power 10, 4s to the power 1 (not 3d to the power 9, 4s to the power 2). One 4s electron shifts to 3d to make it exactly half-filled or fully-filled, which lowers energy. This is a stability effect, not a true violation of Aufbau.

⚠️ The NEET trap
3d fills before 4s because 3 is smaller than 4
4s fills before 3d because the (n+l) value of 4s (4+0=4) is lower than that of 3d (3+2=5)
🧠 Aufbau uses n+l, not n alone. When n+l ties, THEN pick the smaller n. Write out n+l for every orbital in energy questions.

Real NEET questions

NEET 2019

4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is:

A · 5f > 6p > 5p > 4d
B · 6p > 5f > 5p > 4d
C · 6p > 5f > 4d > 5p
D · 5f > 6p > 4d > 5p
Solution: Use the (n+l) rule. 4d: n+l = 4+2 = 6. 5p: n+l = 5+1 = 6. 5f: n+l = 5+3 = 8. 6p: n+l = 6+1 = 7. Higher (n+l) means higher energy, so 5f (8) is highest, then 6p (7). For the tie between 4d and 5p (both 6), the one with higher n has higher energy, so 5p > 4d. Decreasing energy order: 5f > 6p > 5p > 4d. Answer: A.
NEET 2016

Two electrons occupying the same orbital are distinguished by:

A · Principal quantum number
B · Magnetic quantum number
C · Azimuthal quantum number
D · Spin quantum number
Solution: By the Pauli Exclusion Principle, two electrons in the same orbital already share the same n, l and magnetic quantum number (m). To keep all four quantum numbers from being identical, they must differ in the spin quantum number: one has ms = +1/2 and the other ms = -1/2. Answer: D.
NEET 2016

The electronic configurations of Eu (Atomic no. 63), Gd (Atomic No. 64) and Tb (Atomic No. 65), respectively, are:

A · [Xe]4f⁷6s², [Xe]4f⁸6s² and [Xe]4f⁸5d¹6s²
B · [Xe]4f⁶5d¹6s², [Xe]4f⁷5d¹6s² and [Xe]4f⁹6s²
C · [Xe]4f⁶5d¹6s², [Xe]4f⁷5d¹6s² and [Xe]4f⁸5d¹6s²
D · [Xe]4f⁷6s², [Xe]4f⁷5d¹6s² and [Xe]4f⁹6s²
Solution: Filling by Aufbau plus the extra stability of a half-filled 4f subshell: Eu (Z=63) = [Xe]4f⁷6s² (4f is exactly half-filled, so it is stable). Gd (Z=64) keeps the stable half-filled 4f⁷ and the next electron enters 5d: [Xe]4f⁷5d¹6s². Tb (Z=65) = [Xe]4f⁹6s². This matches option D.

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Frequently asked

What is the correct order of the three rules when writing a configuration?

First use Aufbau to pick the next lowest-energy orbital (n+l rule). Then apply Pauli, so each orbital takes at most 2 electrons with opposite spins. Within a set of equal-energy orbitals, apply Hund, filling them singly with parallel spin before pairing. In practice all three work together for each subshell you fill.

Why is 4s written before 3d but emptied first in ions?

4s fills before 3d because it is lower in energy in the neutral atom (n+l rule). But once 3d is occupied, 3d drops below 4s in energy. So when forming cations of transition metals, electrons are removed from 4s first. This is a common NEET point for d-block ions.

Does Hund's rule apply to s orbitals?

No, an s subshell has only one orbital, so there is nothing to spread across. Hund's rule matters only where a subshell has more than one equal-energy orbital: p (3 orbitals), d (5 orbitals) and f (7 orbitals).

How many electrons can one orbital, one subshell, and one shell hold?

One orbital holds 2 electrons (Pauli). A subshell holds 2(2l+1): s holds 2, p holds 6, d holds 10, f holds 14. A shell holds 2n² electrons, where n is the shell number.

What is exchange energy and why does it matter for Hund's rule?

Exchange energy is a stabilising energy that grows when more electrons of the same spin are present in a subshell and can swap positions. Filling orbitals singly with parallel spins (Hund's way) maximises exchange energy, which lowers the atom's energy and explains the extra stability of half-filled and fully-filled subshells.