Magnetic Quantum Number (m_l) and Number of Orbitals = 2l + 1

Chemistry · Structure Of Atom · NEET

The magnetic quantum number (m_l) tells you the orientation of an orbital in space, meaning which way it points. For any subshell, m_l takes all whole-number values from -l to +l, including 0. So the number of orbitals in a subshell is (2l + 1). Memory hook: "minus-l to plus-l, don't forget the ZERO" gives you 2l+1 boxes.
Magnetic Quantum Number: m_l from -l to +l (2l+1 orbitals)l = 0 (s)01 orbitall = 1 (p)-10+13 orbitalsl = 2 (d)-2-10+1+25 orbitalsAlways include 0 in the middle → count = 2l + 1
Each subshell's orbitals are labelled by m_l running from -l to +l (with 0 in the centre). Counting the boxes gives 2l+1: s=1, p=3, d=5. Forgetting the 0 is the top NEET mistake.

Your doubts, answered

What does the magnetic quantum number (m_l) actually tell us?

It tells you the ORIENTATION of an orbital, that is, the direction the orbital points in space. The azimuthal number l fixes the SHAPE (s, p, d, f), but many orbitals of that same shape can point in different directions. m_l labels each of those directions. For NEET, remember: n = size, l = shape, m_l = orientation, m_s = spin.

Why is the number of orbitals equal to 2l + 1?

For a fixed l, m_l is allowed to take every whole number from -l up to +l, and it must include 0. Count them: from -l to +l there are l values below zero, l values above zero, and 1 zero. That is l + l + 1 = 2l + 1. So a subshell always holds (2l+1) orbitals.

Does m_l include zero? Students keep forgetting it.

Yes. Zero is always one of the allowed values. This is the single most common NEET mistake. For l = 2 (d subshell), the correct set is -2, -1, 0, +1, +2 which is 5 values. If you drop the 0 and write only 4 values, the set becomes WRONG, which is exactly how NTA sets traps (see NEET 2023 below).

How many orbitals are in s, p, d and f subshells?

Use 2l+1. s (l=0): 2(0)+1 = 1 orbital. p (l=1): 2(1)+1 = 3 orbitals. d (l=2): 2(2)+1 = 5 orbitals. f (l=3): 2(3)+1 = 7 orbitals. Each orbital can hold 2 electrons, so max electrons are s=2, p=6, d=10, f=14.

What are the m_l values for a d orbital (like 3d)?

For any d subshell l = 2, so m_l = -2, -1, 0, +1, +2. That is 5 orbitals. The label 3d just means n = 3 with l = 2; the m_l values do NOT depend on n, only on l. So 3d, 4d and 5d all have the same five m_l values.

What is the difference between azimuthal (l) and magnetic (m_l) quantum numbers?

l decides the shape and the subshell (l = 0 is s, 1 is p, 2 is d, 3 is f). m_l decides the orientation within that subshell and counts how many orbitals there are, which is 2l+1. In short: l = which subshell, m_l = which orbital inside it.

Can m_l be larger than l or negative?

m_l can be negative (that is normal, it runs from -l upward). But its size can never be bigger than l. The rule is -l is less than or equal to m_l is less than or equal to +l. So for l = 1, m_l = +2 is FORBIDDEN, but m_l = -1 is perfectly allowed.

⚠️ The NEET trap
For l = 2, the magnetic quantum number values are -2, -1, +1, +2 (4 values), so there are 4 d-orbitals.
For l = 2, m_l = -2, -1, 0, +1, +2 which is 5 values, giving 5 d-orbitals. The value 0 must always be included, so the set uses 2l+1 = 5.
🧠 NTA loves to DELETE the zero. Always write minus-l to plus-l and physically place a 0 in the middle. Missing 0 = wrong set.

Real NEET questions

NEET 2023

The relation between n_m (the number of permissible values of the magnetic quantum number m) for a given value of the azimuthal quantum number l is:

A · n_m = 2l + 1
B · l = 2n_m + 1
C · l = (n_m - 1)/2
D · l = n_m + 2
Solution: For a given l, m takes every value from -l to +l including 0, which is (2l+1) values. So the number of orbitals in that subshell, n_m = 2l + 1. Option A is correct.
NEET 2023

The incorrect set of quantum numbers from the following is:

A · n=4, l=2, m_l = -2,-1,0,+1,+2, m_s = -1/2
B · n=5, l=3, m_l = -3,-2,-1,0,+1,+2,+3, m_s = +1/2
C · n=4, l=3, m_l = -3,-2,-1,0,+1,+2,+3, m_s = -1/2
D · n=5, l=2, m_l = -2,-1,+1,+2, m_s = +1/2
Solution: For l = 2, m_l must be -2,-1,0,+1,+2, which is 5 values (2l+1). Option D lists only -2,-1,+1,+2 and drops the 0, so it is an incomplete and therefore incorrect set. This is the classic 'missing zero' trap.
NEET 2024

Match List-I (Quantum Number) with List-II (Information provided): (A) m_l (B) m_s (C) l (D) n ... (I) shape (II) size (III) orientation of orbital (IV) orientation of spin

A · A-III, B-IV, C-I, D-II
B · A-III, B-IV, C-II, D-I
C · A-II, B-I, C-IV, D-III
D · A-I, B-III, C-II, D-IV
Solution: m_l gives orientation of the orbital (III), m_s gives orientation of electron spin (IV), l gives shape (I), and n gives size (II). So A-III, B-IV, C-I, D-II, which is option A.

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Frequently asked

How many orbitals are there in a p subshell?

Three. For p, l = 1, so number of orbitals = 2l+1 = 2(1)+1 = 3. They are p_x, p_y and p_z, corresponding to m_l = -1, 0, +1.

Does the magnetic quantum number depend on n?

No. m_l depends only on l. It runs from -l to +l no matter what n is. That is why 2p, 3p and 4p all have the same three m_l values (-1, 0, +1).

What is the maximum number of electrons decided by m_l?

m_l gives the number of orbitals (2l+1), and each orbital holds 2 electrons (from spin). So the max electrons in a subshell is 2 x (2l+1): s=2, p=6, d=10, f=14.

What does m_l = 0 mean?

It is one allowed orientation of the orbital, not 'no orbital'. For example, in the p subshell m_l = 0 corresponds to the p_z orbital. Zero is a real, valid orbital and must always be counted.

Why is the magnetic quantum number called 'magnetic'?

Because these orbital orientations only become separate energy levels when the atom is placed in a magnetic field (the Zeeman effect). Without a field the (2l+1) orbitals have the same energy (they are degenerate).