Why Is Electric Charge Quantised? (q = ne Explained)

Chemistry · Structure Of Atom · NEET

Charge is "quantised" means charge comes only in whole-number packets of one electron charge (e = 1.6 x 10^-19 C). So any charge q must be q = ne, where n is a whole number (1, 2, 3...). Millikan's oil-drop experiment proved this, because every drop's charge was always a whole-number times e. Memory hook: charge is like buying eggs — you can take 1, 2, or 3 eggs, but never half an egg. "e" is one egg.
Charge comes only in whole packets of e (q = ne)e = 1.6 x 10^-19 C is the smallest packet1en=12en=23en=31.5 enot allowedXAllowed: 1e, 2e, 3e ... Never allowed: 1.5e, 2.4e (fractions of e)Check: q / e must be a whole number -> that is n
Charge always stacks in whole packets of e, so q = ne with n = 1, 2, 3... A fraction like 1.5e can never exist because n must be a whole number.

Your doubts, answered

What does 'charge is quantised' actually mean?

It means electric charge is not smooth or continuous. It comes only in fixed small packets. The smallest packet is the charge of one electron, e = 1.6 x 10^-19 coulomb. Any object's total charge is a whole-number multiple of this packet. You cannot have a bit of charge smaller than e. This is why we write q = ne.

What is 'n' in the formula q = ne?

n is a whole number: 1, 2, 3, 4 and so on (an integer). It counts how many electron-charges are present. If a drop has 3 extra electrons, then n = 3 and q = 3e. n can never be a fraction like 1.5 or 2.7. This is the key point NEET tests.

Can a charge be 1.5 times e or any fraction?

No. Because n must be a whole number, q can be 1e, 2e, 3e, but never 1.5e or 2.5e. If a question gives you a charge that is NOT a whole-number multiple of 1.6 x 10^-19 C, that value is not possible for a real charged body. (Note: quarks have fractional charge inside the nucleus, but they are never found free, so at NEET level the smallest free charge is e.)

How did Millikan prove charge is quantised?

In his oil-drop experiment, Millikan measured the charge on many tiny oil drops. Every single drop had a charge that was a whole-number multiple of 1.6 x 10^-19 C. For example, drops had charges like 1e, 2e, 3e, but never something in between. Since e was always the common building block, he concluded charge is quantised and q = ne.

What is the smallest possible charge on any body?

The smallest free charge is the charge of one electron (or one proton), e = 1.6 x 10^-19 C. A neutral body has n = 0. A charged body has at least n = 1. So no charged object can carry less than e.

Is q = ne only about electrons, or protons too?

Both. A proton carries +e and an electron carries -e (same size, opposite sign). Removing electrons leaves a positive charge (still a multiple of e), and adding electrons gives a negative charge. Either way, the total is always n times e, so q = ne holds for positive and negative charges.

⚠️ The NEET trap
Picking a charge value that is not a whole-number multiple of e, like 4.8 x 10^-19 / 2 = 2.4 x 10^-19 C, and thinking any charge is allowed.
A charge is possible only if q / e is a whole number. 4.8 x 10^-19 C is allowed because 4.8/1.6 = 3 (n = 3). But 2.4 x 10^-19 C is NOT allowed because 2.4/1.6 = 1.5, which is a fraction.
🧠 Always divide the given charge by 1.6 x 10^-19. If you do not get a clean whole number, that charge cannot exist. n must be an integer.

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Frequently asked

What is the formula for quantisation of charge?

q = ne, where q is the total charge, e = 1.6 x 10^-19 C is the charge of one electron, and n is a whole number (integer).

Who discovered that charge is quantised?

Robert Millikan, through his famous oil-drop experiment, measured the charge on the electron and showed all charges are whole-number multiples of e.

Why is quantisation of charge important for NEET?

NEET often gives a charge value and asks if it is possible, or asks how many electrons were transferred (n = q/e). Knowing q = ne with integer n lets you solve these fast.

Can n be zero in q = ne?

Yes. n = 0 means no extra charge, so the body is neutral (q = 0). For a charged body, n is 1 or more.

Does quantisation of charge apply to positive charges too?

Yes. A proton has charge +e. Removing electrons gives a positive charge that is still a whole-number multiple of e, so q = ne works for both signs.