Consider the molecules CH4, NH3 and H2O. Which of the given statements is false?

NEET 2016 Phase 1 · ChemistryVSEPR shapePrevious Year Question

Consider the molecules $CH X_{4}$ , $NH X_{3}$ and $H X_{2} O$ . Which of the given statements is false?

Answer: (B) The H–O–H bond angle in $H X_{2} O$ is larger than the H–C–H bond angle in $CH X_{4}$ .. \textbf{Answer:} (B) The H–O–H bond angle in $H X_{2} O$ is larger than the H–C–H bond angle in $CH X_{4}$ .

A.The H–C–H bond angle in $CH X_{4}$ , the H–N–H bond angle in $NH X_{3}$ , and the H–O–H bond angle in $H X_{2} O$ are all greater than $9 0^{\circ}$ .
B.The H–O–H bond angle in $H X_{2} O$ is larger than the H–C–H bond angle in $CH X_{4}$ .✓
C.The H–O–H bond angle in $H X_{2} O$ is smaller than the H–N–H bond angle in $NH X_{3}$ .
D.The H–C–H bond angle in $CH X_{4}$ is larger than the H–N–H bond angle in $NH X_{3}$ .

Correct Answer

(B) The H–O–H bond angle in $H X_{2} O$ is larger than the H–C–H bond angle in $CH X_{4}$ .

Solution & Explanation

\textbf{Answer:} (B) The H–O–H bond angle in $H X_{2} O$ is larger than the H–C–H bond angle in $CH X_{4}$ . \textbf{Solution:} All three are $s p^{3}$ hybridized. Increasing lone pairs increase lp–bp repulsion and shrink the angle: $CH X_{4}$ ( $109. 5^{\circ}$ ) > $NH X_{3}$ ( $10 7^{\circ}$ ) > $H X_{2} O$ ( $104. 5^{\circ}$ ). So the angle in $H X_{2} O$ is smaller, not larger, than that in $CH X_{4}$ — statement B is false.

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Solution & Explanation

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Consider the molecules $CH X_{4}$ , $NH X_{3}$ and $H X_{2} O$ . Which of the given statements is false?