NEET 2016 Phase 1 · ChemistryIonic characterPrevious Year Question

Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules?

Answer: (B) $Cl X_{2}$ > $Br X_{2}$ > $F X_{2}$ > $I X_{2}$ . \textbf{Answer:} (B) $Cl X_{2}$ > $Br X_{2}$ > $F X_{2}$ > $I X_{2}$ \textbf{Solution:} Bond dissociation enthalpy order is $Cl X_{2}$ > $Br X_{2}$ > $F X_{2}$ > $I X_{2}$ .

A. $I X_{2}$ > $Br X_{2}$ > $Cl X_{2}$ > $F X_{2}$
B. $Cl X_{2}$ > $Br X_{2}$ > $F X_{2}$ > $I X_{2}$ ✓
C. $Br X_{2}$ > $I X_{2}$ > $F X_{2}$ > $Cl X_{2}$
D. $F X_{2}$ > $Cl X_{2}$ > $Br X_{2}$ > $I X_{2}$

Correct Answer

(B) $Cl X_{2}$ > $Br X_{2}$ > $F X_{2}$ > $I X_{2}$

Solution & Explanation

\textbf{Answer:} (B) $Cl X_{2}$ > $Br X_{2}$ > $F X_{2}$ > $I X_{2}$ \textbf{Solution:} Bond dissociation enthalpy order is $Cl X_{2}$ > $Br X_{2}$ > $F X_{2}$ > $I X_{2}$ . $F X_{2}$ is anomalously low because of large lone-pair/lone-pair electron repulsion in the small $F X_{2}$ molecule, placing it below $Cl X_{2}$ and $Br X_{2}$ .

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