NEET 2016 Phase 1 · PhysicsPrevious Year Question

An astronomical telescope has objective and eyepiece of focal lengths 40 cm and 4 cm respectively. To view an object 200 cm away from the objective, the lenses must be separated by a distance

Answer: (D) 54.0 cm. Answer: (D) 54.0 cm Solution: The object is at a finite distance, so first find the image formed by the objective.

  1. A.37.3 cm
  2. B.46.0 cm
  3. C.50.0 cm
  4. D.54.0 cm

Correct Answer

(D) 54.0 cm

Solution & Explanation

Answer: (D) 54.0 cm Solution: The object is at a finite distance, so first find the image formed by the objective. Objective: f₀ = 40 cm, u = −200 cm. 1/v − 1/u = 1/f₀ 1/v = 1/40 + 1/(−200) = 5/200 − 1/200 = 4/200 = 1/50 v = 50 cm (real image, 50 cm behind the objective). For relaxed viewing this image lies at the focus of the eyepiece, so the eyepiece is placed a further f_e = 4 cm beyond it. Separation = v + f_e = 50 + 4 = 54.0 cm.

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