NEET 2016 Phase 1 · PhysicsPower in L,CPrevious Year Question

A small signal voltage V(t) = V₀ sin ωt is applied across an ideal capacitor C:

Answer: (B) Over a full cycle the capacitor C does not consume any energy from the voltage source. Answer: (B) Over a full cycle the capacitor C does not consume any energy from the voltage source Solution: In a purely capacitive AC circuit the current leads the voltage by 90° (not lags, not 180°, not in phase).

  1. A.Current I(t), lags voltage V(t) by 90°
  2. B.Over a full cycle the capacitor C does not consume any energy from the voltage source
  3. C.Current I(t) is in phase with voltage V(t).
  4. D.Current I(t) leads voltage V(t) by 180°

Correct Answer

(B) Over a full cycle the capacitor C does not consume any energy from the voltage source

Solution & Explanation

Answer: (B) Over a full cycle the capacitor C does not consume any energy from the voltage source Solution: In a purely capacitive AC circuit the current leads the voltage by 90° (not lags, not 180°, not in phase). Since the phase difference is 90°, the average power = V_rms·I_rms·cos 90° = 0, so over a full cycle the ideal capacitor consumes no energy (wattless current).

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